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    Maths-
    General
    Easy

    Question

    text  If  end text x cos space theta equals y cos space open parentheses theta plus fraction numerator 2 pi over denominator 3 end fraction close parentheses equals z cos space open parentheses theta plus fraction numerator 4 pi over denominator 3 end fraction close parentheses then the value of 1 over x plus 1 over y plus 1 over z equals

    1. 1
    2. 2
    3. 0
    4. 3 cos space theta

    The correct answer is: 0

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    text  If  end text 0 less than alpha comma beta less than pi over 4 comma cos space left parenthesis alpha plus beta right parenthesis equals 4 over 5 comma sin space left parenthesis alpha minus beta right parenthesis equals 5 over 13 text  then  end text tan text end text 2 alpha equals

    text  If  end text 0 less than alpha comma beta less than pi over 4 comma cos space left parenthesis alpha plus beta right parenthesis equals 4 over 5 comma sin space left parenthesis alpha minus beta right parenthesis equals 5 over 13 text  then  end text tan text end text 2 alpha equals

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    if tan space left parenthesis A minus B right parenthesis equals 7 divided by 24 comma tan space A equals 4 divided by 3 where A, B acute, then A+B=

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    text  If  end text cos space A equals 5 over 13 comma tan space B equals fraction numerator negative 15 over denominator 8 end fraction comma negative 270 to the power of ring operator less than straight A less than 360 to the power of ring operator comma 90 to the power of ring operator less than straight B less than 180 to the power of ring operator, then the quadrant to which A+B belongs is

    text  If  end text cos space A equals 5 over 13 comma tan space B equals fraction numerator negative 15 over denominator 8 end fraction comma negative 270 to the power of ring operator less than straight A less than 360 to the power of ring operator comma 90 to the power of ring operator less than straight B less than 180 to the power of ring operator, then the quadrant to which A+B belongs is

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    In a triangle A B C comma fraction numerator t a n invisible function application B over denominator t a n invisible function application C end fraction equals 2 over 3 and t a n invisible function application A t a n invisible function application B t a n invisible function application C equals 6 then the value(s) satisfy the equation

    In a triangle A B C comma fraction numerator t a n invisible function application B over denominator t a n invisible function application C end fraction equals 2 over 3 and t a n invisible function application A t a n invisible function application B t a n invisible function application C equals 6 then the value(s) satisfy the equation

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    t a n space 40 to the power of ring operator plus t a n space 80 to the power of ring operator minus √ 3 t a n space 40 to the power of ring operator t a n space 80 to the power of ring operator equals

    t a n space 40 to the power of ring operator plus t a n space 80 to the power of ring operator minus √ 3 t a n space 40 to the power of ring operator t a n space 80 to the power of ring operator equals

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    text  If  end text 0 less than theta less than pi over 2 text  and  end text 2 sin invisible function application theta equals square root of 3 cos space 10 to the power of ring operator plus sin space 10 to the power of ring operator text  then  end text theta equals

    text  If  end text 0 less than theta less than pi over 2 text  and  end text 2 sin invisible function application theta equals square root of 3 cos space 10 to the power of ring operator plus sin space 10 to the power of ring operator text  then  end text theta equals

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    cos space left parenthesis n plus 1 right parenthesis alpha cos space left parenthesis n minus 1 right parenthesis alpha plus sin space left parenthesis n plus 1 right parenthesis alpha sin space left parenthesis n minus 1 right parenthesis alpha equals

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    sin space 40 to the power of ring operator 35 cos space 19 to the power of ring operator 25 plus cos space 40 to the power of ring operator 35 to the power of ring operator sin space 19 to the power of ring operator 25 equals

    sin space 40 to the power of ring operator 35 cos space 19 to the power of ring operator 25 plus cos space 40 to the power of ring operator 35 to the power of ring operator sin space 19 to the power of ring operator 25 equals

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    Assertion A: In a right-angled triangle s i n squared space A plus s i n squared space B plus s e c squared space C equals 2 Reason R colonif alpha comma beta are complementary angles then s i n squared space alpha plus s i n squared space beta equals 1

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    AB is a line segment of length 24 cm and C is its middle point. On AB, A and CB semi-circles are described. The radius of circle which touches all these semi-circles is

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    in a triangle P Q R 3 sin space P plus 4 cos space Q equals 6 and 4 sin space Q plus 3 cos p=1 then

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    The expression fraction numerator tan space A over denominator 1 minus cat space A end fraction plus fraction numerator cot space A over denominator 1 minus tan space d end fraction can be written as

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    if straight f subscript straight k left parenthesis straight x right parenthesis equals 1 divided by straight k left parenthesis sin to the power of straight k space straight x plus cos to the power of straight k space straight x right parenthesis where straight x element of straight R comma straight k greater or equal than 1 then straight f subscript 4 left parenthesis straight x right parenthesis minus straight f subscript 6 left parenthesis straight x right parenthesis equals

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    Two arcs of same length of two different circles subtended angles of  25 to the power of ring operator and 75 to the power of ring operator  at their centers respectively. Then the ratio of the radii of the circles is

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    Let theta element of left parenthesis 0 comma pi divided by 4 right parenthesis and straight t subscript 1 equals left parenthesis tan space theta right parenthesis to the power of me theta end exponent comma straight t subscript 2 equals left parenthesis tan space theta right parenthesis to the power of cot space theta end exponent comma straight t subscript 3 equals left parenthesis cot space theta right parenthesis to the power of con space theta end exponent straight t subscript 4 equals left parenthesis cot space theta right parenthesis to the power of cos space theta end exponent then

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