Maths-
General
Easy

Question

In any ΔABC having sides a, b, c opposite to angles A, B, C respectively, then-

  1. a sin invisible function application open parentheses fraction numerator B minus C over denominator 2 end fraction close parentheses equals left parenthesis b minus c right parenthesis cos invisible function application A over 2
  2. a cos invisible function application A over 2 equals left parenthesis b minus c right parenthesis sin invisible function application fraction numerator B minus C over denominator 2 end fraction
  3. a cos invisible function application A over 2 equals left parenthesis b plus c right parenthesis sin invisible function application fraction numerator B plus C over denominator 2 end fraction
  4. a sin invisible function application fraction numerator straight B plus straight C over denominator 2 end fraction equals left parenthesis b plus c right parenthesis cos invisible function application straight A over 2

The correct answer is: a sin invisible function application open parentheses fraction numerator B minus C over denominator 2 end fraction close parentheses equals left parenthesis b minus c right parenthesis cos invisible function application A over 2

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