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General
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Question

A man travelling east at 8km/h finds that the wind seems to blow directly from the north. On doubling the speed, he finds that it appears to come from the north-east. The velocity of the wind is

  1. theta equals 45 to the power of ring operator end exponent comma v equals 8 square root of 2    
  2. theta equals negative 45 to the power of ring operator end exponent comma v equals 8 square root of 2    
  3. theta equals 90 to the power of 0 end exponent comma v equals 4 square root of 2    
  4. theta equals 60 to the power of ring operator end exponent comma v equals 8 square root of 2    

The correct answer is: theta equals negative 45 to the power of ring operator end exponent comma v equals 8 square root of 2


    The velocity of wind relative to man = Actual velocity of wind-Actual velocity of man
    Let i plus j represent unit vectors along east and north. Let the actual velocity of wind be given by
    x i plus y j
    In the first case the man’s velocity is 8i and that of the wind blowing from the north relative to the man is
    negative p j
    Therefore
    negative p stack j with hat on top equals open parentheses x stack i with hat on top plus y stack j with hat on top close parentheses minus 8 stack i with hat on top open parentheses b y open parentheses i close parentheses close parentheses
    Comparing coefficients x-8=0 , y=-p In the second case when the man doubles his speed, it seems to come from the north -east
    table row cell negative q open parentheses stack i with hat on top plus stack j with hat on top close parentheses equals open parentheses x stack i with hat on top plus y stack j with hat on top close parentheses minus 16 stack i with hat on top end cell row cell therefore x minus 16 equals negative q comma y equals negative q end cell row cell text end text text P end text text u end text text t end text text t end text text i end text text n end text text g end text text end text x equals 8 comma text end text text w end text text e end text text end text text g end text text e end text text t end text text end text q equals 8 end cell row cell y equals negative 8 end cell end table
    Hence, the velocity of wind is
    x stack i with hat on top plus y stack j with hat on top equals 8 open parentheses stack i with hat on top minus stack j with hat on top close parentheses
    Its magnitude is
    square root of open parentheses 8 to the power of 2 end exponent plus 8 to the power of 2 end exponent close parentheses end root equals 8 square root of 2 text  and  end text tan invisible function application theta equals negative 1
    theta equals negative 45 to the power of 0 end exponent. Hence , its direction is from the north -west

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