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Maths-

General

Easy

Question

If $left parenthesis 1 plus X plus x to the power of 2 right parenthesis to the power of n equals a subscript 0 plus a subscript 1 x plus a subscript 2 x squared plus end exponent$ $plus a subscript 2 n end subscript x to the power of 2 n end exponent$ then $a subscript 0 end subscript plus a subscript 3 end subscript plus a subscript 6 end subscript plus negative negative negative negative negative equals$

$3^{n}$
$3^{n - 1}$
$3^{n - 2}$
1

The correct answer is: $3 to the power of n minus 1 end exponent$

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