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Question

If AB makes 90º angle at the vertex of parabola then -

  1. t1t2 = – 1    
  2. t1t2 = – 4    
  3. t1 = fraction numerator 2 over denominator t subscript 2 end subscript end fraction    
  4. t2 = – fraction numerator 2 over denominator t subscript 1 end subscript end fraction    

The correct answer is: t1t2 = – 4



    θ = 90º therefore(slope of OA) (slope of OB) = – 1
    2at1 – 0/at12 – 0 × 2at2 – 0/at22 – 0 = – 1
    2/t1 × 2/t2 = – 1
    therefore t1t2 = – 4

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