Question
x – 2 = t2, y = 2t are the parametric equations of the parabola
- y2 = 4x
- y2 = – 4x
- x2 = – 4y
- y2 = 4(x – 2)
Hint:
replace the value of y into the first equation.
The correct answer is: y2 = 4(x – 2)
y2=4(x-2)
X=2 +t2
y = 2t
t=y/2
x= 2+(y/2)2
x= 2 + y2/4
4x= 8 + y2
y2 = 4x -8=4(x-2)
parametric form gives us the general coordinates of the curve. we can solve for the two to build the relationship between the x and y coordinates which gives us the locus
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