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Question

If any tangent to the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 intercepts equal lengths ell on the axes, then ell =

  1. square root of a to the power of 2 end exponent plus b to the power of 2 end exponent end root    
  2. a2 + b2    
  3. (a2 + b2)2    
  4. None of these    

hintHint:

find out the equation of tangent of ellipse in slope form. find the x and y intercepts and equate them

The correct answer is: square root of a to the power of 2 end exponent plus b to the power of 2 end exponent end root


    square root of a to the power of 2 end exponent plus b to the power of 2 end exponent end root


    Tangent to the ellipse : y= mx + √a2m2+b2
    x intercept = -( √a2m2+b2 )/m
    y intercept = √a2m2+b2
    according to the problem,

    √a2m2+b2 = -( √a2m2+b2 )/m
    => m=-1
    Intercept =  √a2+b2

    x intercept is the x coordinate at which the curve cuts the x axis and similarly for y intercept, the y axis is considered.

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