Physics-
General
Easy

Question

In an apparatus, the electric field was found to oscillate with amplitude of 18 V/m. The amplitude of the oscillating magnetic field will be

  1. 4 cross times 10 to the power of negative 6 end exponent T    
  2. 6 cross times 10 to the power of negative 8 end exponent T    
  3. 9 cross times 10 to the power of negative 9 end exponent T    
  4. 11 cross times 10 to the power of negative 11 end exponent T    

The correct answer is: 6 cross times 10 to the power of negative 8 end exponent T

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