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Easy

Question

Integrating factor of differential equation cos invisible function application x fraction numerator d y over denominator d x end fraction plus y sin invisible function application x equals 1 is

  1. cos invisible function application x    
  2. tan invisible function application x    
  3. sec invisible function application x    
  4. sin invisible function application x    

The correct answer is: sec invisible function application x


    fraction numerator d y over denominator d x end fraction plus y tan invisible function application x equals sec invisible function application x
    I.F. equals e to the power of not stretchy integral tan invisible function application x d x end exponent equals e to the power of logsec invisible function application x end exponent equals sec invisible function application x

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