Question
Let and are two arithmetic sequences such that and then the value of is
- 8/3
- 3/2
- 19/8
- 2
Hint:
use the formula Sn = (n/2)( 2 a1 + (n-1)d)
for the summation.
The correct answer is: 19/8
19/8
given, s1=t1 ; s2 = 2t2
let s2- s1 = d1 and t2-t1 = d2
s2-s1 = 2t2-t1 = d1
given,
summation (i=1 to 10) si = summation ( i= 1 to 15) ti
=> (10/2)( 2s1 + 9 d1) = (15/2) (2t1 + 14 d2)
on solving, we get
2s1 +9d1 = 3t1 + 21 d2
substituting the values of s1, d1 and d2 into this equation, we get
2t1 + 9(2t2-t1)=3t1+21(t2-t1)
or
3t2=11t1
substituting the value of t2 into the equation (s2-s1)/(t2-t1) we get
(2t2-t1)/(t2-t1)= (22/3-1)/(11/3-1)
= 19/8
an A.P is a sequence of mathematical terms which have a common difference with their adjacent elements
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