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Let a matrix A =open square brackets table row 1 1 row 0 1 end table close square brackets & P =open square brackets table row cell fraction numerator square root of 3 over denominator 2 end fraction end cell cell fraction numerator 1 over denominator 2 end fraction end cell row cell negative fraction numerator 1 over denominator 2 end fraction end cell cell fraction numerator square root of 3 over denominator 2 end fraction end cell end table close square brackets Q = PAPT where PT is transpose of matrix P. Find PT Q2005 P is

  1. open square brackets table row 1 2005 row 0 1 end table close square brackets    
  2. 1 fourth open square brackets table row cell 1 plus 2005 square root of 3 end cell 6015 row 2005 cell 1 minus 2005 square root of 3 end cell end table close square brackets    
  3. 1 fourth open square brackets table row cell 1 plus 2005 square root of 3 end cell 2005 row 2005 cell 1 minus 2005 square root of 3 end cell end table close square brackets    
  4. open square brackets table row 2005 2005 row 0 1 end table close square brackets    

The correct answer is: open square brackets table row 1 2005 row 0 1 end table close square brackets

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