Maths-
SAT
Easy

Question

P(x) = x2 - 11x+ k
In the function above, k is a constant. If 2 is a zero of the function, what is the value of k ?

  1. -18
  2. -2
  3. 3
  4. 18

The correct answer is: 18


    P (x) = x2 – 11x + k
    2 is zero = P (2) = 0
    P (2) = 22 – 11 (2) + k = 0
    4 – 22 + k = 0
    K = 18

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