Question
Statement-I : If x2y3 = 6(x, y > 0), then the least value of 3x + 4y is 10
Statement-II : If m1, m2 N, a1, a2 > 0 then and equality holds when a1 = a2.
- Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.
- Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I.
- Statement-I is true, Statement-II is false.
- Statement-I is false, Statement-II is true.
Hint:
apply the AM GM rule
The correct answer is: Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.
Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.
If we break 3x into two parts 3x/2 ,3x/2 and 4y into three parts 4y/3 ,4y/3,4y/3 and then apply the AM>=GM rule, we get
(3x/2+3x/2+ 4y/3+4y/3+4y/3)/5>=((3x/2)2(4y/3)3)1/5
y3= 6/x2
we get
(3x+4y)/5>= 2
3x+4y>=10
Statement 1 is true.
Let there be a1,a1,a1….m1 times ,a2,a2,a2….m2 times.
Applying the AM>=GM rule, we get the Statement 2. Hence, both are true.
the AM GM rule is valid for any set of natural numbers, i.e., numbers > 0.
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