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Maths-

General

Easy

Question

The domain of the function $f open parentheses x close parentheses equals fraction numerator sin to the power of 1 end exponent invisible function application left parenthesis x minus 3 right parenthesis over denominator square root of 9 minus x to the power of 2 end exponent end root end fraction$ is

[2, 3]
[2,3)
[1, 2]
[1, 2)

The correct answer is: [2,3)

The function $f left parenthesis x right parenthesis$ will be defined, if
$negative 1 less or equal than open parentheses x minus 3 close parentheses less or equal than 1 rightwards double arrow blank 2 less or equal than x less or equal than 4$
And $9 minus x to the power of 2 end exponent greater than 0 blank rightwards double arrow blank minus 3 less than x less than 3$
$therefore blank 2 less or equal than x less than 3$

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