Maths-
General
Easy
Question
The equation of the tangent to the parabola y = (x – 3)2 parallel to the chord joining the points (3, 0) and (4, 1) is -
- 2x – 2y + 6 = 0
- 2y – 2x + 6 = 0
- 4y – 4x + 13 = 0
- 4x + 4y = 13
The correct answer is: 4y – 4x + 13 = 0
y' = 2(x –1) = 1 gives the point 
and the required tangent is y –
= 1. 
or 4y – 4x + 13 = 0.
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