Maths-
General
Easy
Question
the focus of parabola (y – k)2 = 4 (x – h) always lies between the line x + y = 1 and x + y = 3 then -
- 0
h + k 2
- 0 h + k 1
- 1 h + k 2
- 1 h + k 3
h + k 2
h + k 1
h + k 2
h + k 3
The correct answer is: 0 h + k 2
To find the correct option.
Focus of the parabola is (h+1,k)
It is given that focus lies between x+y=1 and x+y=3
1<x+y<3
1<h+1+k<3
0<h+k<2
Therefore, 0<h+k<2 is the correct option.
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