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Physics-

General

Easy

Question

Statement 1:Sound waves cannot propagate through vacuum but light waves can
Statement 2:Sound waves cannot be polarised but light waves can be polarized

Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1
Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1
Statement 1 is True, Statement 2 is False
Statement 1 is False, Statement 2 is True

The correct answer is: Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1

Sound waves cannot propagate through vacuum because sound waves are mechanical waves. Light waves can propagate through vacuum because light waves are electromagnetic waves. Since sound waves are longitudinal waves, the particles moves in the direction of propagation, therefore these waves cannot be polarised

Related Questions to study

Straight line $ell$ x + my + n = 0 touches parabola y² = 4ax if $ell$ n = am^k then k =

Straight line $ell$ x + my + n = 0 touches parabola y² = 4ax if $ell$ n = am^k then k =

If $ell$ ₁ & $ell$ ₂ are length of segments of focal chord of parabola y² = 4ax than harmonic mean of $ell$ ₁ & $ell$ ₂ is equal to

If $ell$ ₁ & $ell$ ₂ are length of segments of focal chord of parabola y² = 4ax than harmonic mean of $ell$ ₁ & $ell$ ₂ is equal to

Four similar point masses (each of mass m) are placed on the circumference of a disc of mass M and radius R. The M.I. of the system about the normal axis through the centre O will be:-

Four similar point masses (each of mass m) are placed on the circumference of a disc of mass M and radius R. The M.I. of the system about the normal axis through the centre O will be:-

physics-General

parallel

We have a rectangular slab of same thickness. E, F, G, H are the middle point of AB, BC, CD and AD respectively then which of the following axis the moment of inertia will be minimum :–

We have a rectangular slab of same thickness. E, F, G, H are the middle point of AB, BC, CD and AD respectively then which of the following axis the moment of inertia will be minimum :–

physics-General

Angle between tangents drawn from (1, 4) to parabola y² = 4x is

Angle between tangents drawn from (1, 4) to parabola y² = 4x is

Let y² = 4ax be parabola and PQ be a focal chord of parabola. Let T be the point of intersection of tangents at P and Q. Then

Let y² = 4ax be parabola and PQ be a focal chord of parabola. Let T be the point of intersection of tangents at P and Q. Then

parallel

If the line 2x – 1 = 0 is the derectrix of the parabola y² – kx + 6 = 0 then one of the value of K is -

If the line 2x – 1 = 0 is the derectrix of the parabola y² – kx + 6 = 0 then one of the value of K is -

If a double ordinate of the parabola y² = 4ax be of length 8a, then the angle between the lines joining the vertex of the parabola to the ends of this double ordinate is

If a double ordinate of the parabola y² = 4ax be of length 8a, then the angle between the lines joining the vertex of the parabola to the ends of this double ordinate is

Tangents are drawn from a point P to the parabola y² = 8x such that the slope of one tangent is twice the slope of other. The locus of P is

Tangents are drawn from a point P to the parabola y² = 8x such that the slope of one tangent is twice the slope of other. The locus of P is

parallel

In the adjoining figure along which axis the moment of inertia of the triangular lamina will be maximum- [Given that $A B less than B C less than A C right square bracket$

In the adjoining figure along which axis the moment of inertia of the triangular lamina will be maximum- [Given that $A B less than B C less than A C right square bracket$

physics-General

Three particles, each of mass m are situated at the vertices of an equilateral triangle ABC of side $lambda$ cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram $c m to the power of 2 end exponent$ units will be :

Three particles, each of mass m are situated at the vertices of an equilateral triangle ABC of side $lambda$ cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram $c m to the power of 2 end exponent$ units will be :

physics-General

The locus of the middle points of chords of a parabola which subtend a right angle at the vertex of the parabola is

The locus of the middle points of chords of a parabola which subtend a right angle at the vertex of the parabola is

parallel

If the parabola y² = 4ax passes through (3, 2), then length of latus rectum of the parabola is

If the parabola y² = 4ax passes through (3, 2), then length of latus rectum of the parabola is

The locus of the poles of focal chord of the parabola y² = 4ax is

The locus of the poles of focal chord of the parabola y² = 4ax is

The locus of the mid points of the chords of the parabola y² = 4ax which passes through a given point (β, $proportional to$ )

The locus of the mid points of the chords of the parabola y² = 4ax which passes through a given point (β, $proportional to$ )

parallel

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