Maths-
General
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Question

The formula [where f(xn–1) and f(xn)have opposite sign at each step,n space greater or equal than 1 ] of method of False Position of successive approximation to find the approximate value of a root of the equation f(x)=0 is

  1. x subscript n plus 1 end subscript equals x subscript n end subscript minus fraction numerator f left parenthesis x subscript n end subscript right parenthesis minus f left parenthesis x subscript n minus 1 end subscript right parenthesis over denominator f left parenthesis x subscript n end subscript right parenthesis end fraction left parenthesis x subscript n end subscript minus x subscript n minus 1 end subscript right parenthesis    
  2. x subscript n plus 1 end subscript equals x subscript n end subscript minus fraction numerator f left parenthesis x subscript n end subscript right parenthesis over denominator f left parenthesis x subscript n end subscript right parenthesis minus f left parenthesis x subscript n minus 1 end subscript right parenthesis end fraction left parenthesis x subscript n end subscript minus x subscript n minus 1 end subscript right parenthesis    
  3. x subscript n plus 1 end subscript equals x subscript n end subscript plus fraction numerator f left parenthesis x subscript n end subscript right parenthesis plus f left parenthesis x subscript n minus 1 end subscript right parenthesis over denominator f left parenthesis x subscript n end subscript right parenthesis end fraction left parenthesis x subscript n end subscript minus x subscript n minus 1 end subscript right parenthesis    
  4. x subscript n plus 1 end subscript equals x subscript n end subscript plus fraction numerator f left parenthesis x subscript n end subscript right parenthesis over denominator f left parenthesis x subscript n end subscript right parenthesis plus f left parenthesis x subscript n minus 1 end subscript right parenthesis end fraction left parenthesis x subscript n end subscript minus x subscript n minus 1 end subscript right parenthesis    

The correct answer is: x subscript n plus 1 end subscript equals x subscript n end subscript minus fraction numerator f left parenthesis x subscript n end subscript right parenthesis over denominator f left parenthesis x subscript n end subscript right parenthesis minus f left parenthesis x subscript n minus 1 end subscript right parenthesis end fraction left parenthesis x subscript n end subscript minus x subscript n minus 1 end subscript right parenthesis


    It is obvious.

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