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Maths-

General

Easy

Question

The inverse of the matrix $open square brackets table row 3 cell negative 2 end cell row 1 4 end table close square brackets$ is

$[\begin{matrix} \frac{4}{14} & \frac{2}{14} \\ \frac{- 1}{14} & \frac{3}{14} \end{matrix}]$
$[\begin{matrix} \frac{3}{14} & \frac{- 2}{14} \\ \frac{1}{14} & \frac{4}{14} \end{matrix}]$
$[\begin{matrix} \frac{4}{14} & \frac{- 2}{14} \\ \frac{1}{14} & \frac{3}{14} \end{matrix}]$
$[\begin{matrix} \frac{3}{14} & \frac{2}{14} \\ \frac{1}{14} & \frac{4}{14} \end{matrix}]$

The correct answer is: $open square brackets table row cell fraction numerator 4 over denominator 14 end fraction end cell cell fraction numerator 2 over denominator 14 end fraction end cell row cell fraction numerator negative 1 over denominator 14 end fraction end cell cell fraction numerator 3 over denominator 14 end fraction end cell end table close square brackets$

Let $A equals open square brackets table row 3 cell negative 2 end cell row 1 4 end table close square brackets rightwards double arrow vertical line A vertical line equals 14$
$therefore a d j A equals open square brackets table row 4 2 row cell negative 1 end cell 3 end table close square brackets$ $rightwards double arrow$ $A to the power of negative 1 end exponent equals open square brackets table row cell fraction numerator 4 over denominator 14 end fraction end cell cell fraction numerator 2 over denominator 14 end fraction end cell row cell fraction numerator negative 1 over denominator 14 end fraction end cell cell fraction numerator 3 over denominator 14 end fraction end cell end table close square brackets$ .

Related Questions to study

The ad joint of $open square brackets table row 1 1 1 row 1 2 cell negative 3 end cell row 2 cell negative 1 end cell 3 end table close square brackets$ is

The ad joint of $open square brackets table row 1 1 1 row 1 2 cell negative 3 end cell row 2 cell negative 1 end cell 3 end table close square brackets$ is

The reaction of ethanol with $H subscript 2 S O subscript 4$ does not give:

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An aqueous solution of ethyl alcohol:

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A reflecting surface is represented by the equation $Y equals fraction numerator 2 L over denominator pi end fraction s i n invisible function application open parentheses fraction numerator pi x over denominator L end fraction close parentheses comma 0 0 less or equal than x less or equal than L$ A ray travelling horizontally as shown in figure and becomes vertical after reflection The coordinates of the point (s) where this ray is incident is

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physics-General

A particle is dropped to move along the axis of a concave mirror of focal length f from a height f/2 as shown in the figure The acceleration due to gravity is g Find the maximum speed of the image

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The co-ordinates of image of point object P formed after two successive reflection in situation as shown in figure considering first reflection at concave mirror and then at convex

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physics-General

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A beam of light strikes one mirror of a right angle mirror assembly at an angle of incidence 45⁰ as shown in the figure The right angle mirror assembly is rotated such that the angle of incidence becomes 60⁰ Which of the following statements is (are) correct about the emerging light beam

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A boy is walking under an inclined mirror at a constant velocity V m/s along the X axis as shown in figure If the mirror is inclined at an angle q with the horizontal then what is the velocity of the image?

A boy is walking under an inclined mirror at a constant velocity V m/s along the X axis as shown in figure If the mirror is inclined at an angle q with the horizontal then what is the velocity of the image?

physics-General

Let $A equals open square brackets table row 1 0 0 row 5 2 0 row cell negative 1 end cell 6 1 end table close square brackets$ , then the ad joint of A is

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parallel

If there be a compound of the formula $C H subscript 3 C left parenthesis O H right parenthesis subscript 3 comma$ which one of the following compounds would be obtained form it without treatment with any reagent?

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chemistry-General

An object ‘O’ is placed infront of a small plane mirrorM₁ and a large convex mirrorM₂ of focal length f The distance between ‘O’ and M₁ is x and the distance between M₁ and M₂ is y The image of ‘O’ formed by M₁ and M₂ coincide The magnitude of ‘f’ is

An object ‘O’ is placed infront of a small plane mirrorM₁ and a large convex mirrorM₂ of focal length f The distance between ‘O’ and M₁ is x and the distance between M₁ and M₂ is y The image of ‘O’ formed by M₁ and M₂ coincide The magnitude of ‘f’ is

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Consider a disc rotating in the horizontal plane with a constant angular speed $omega$ about its centre $O$ . The disc has a shaded region on one side of the diameter and an unshanded region on the other side as shown in the figure. When the disc is in the orientation as shown, two pebbles $P$ and $Q$ are simultaneously projected at an angle towards $R$ . The velocity of projection is in the $y minus z$ plane and is same for both pebbles with respect to the disc. Assume that i) they land back on the disc before the disc has completed $fraction numerator 1 over denominator 8 end fraction$ rotation. ii) their range is less than half the disc radius, and iii) $omega$ remains constant throughout. Then

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The resultant of a system of forces shown in figure is a force of 10 N parallel to given forces through $R$ , where $P R$ equals

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physics-General

On reacting with neutral ferric chloride, phenol gives

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An air bubble in glass (m =1.5) is situated at a distance 3 cm from a convex surface of diameter 10 cm as shown The distance from surface at which the image of bubble appears is

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