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Maths-

General

Easy

Question

The number of positive integral solutions of the inequation $fraction numerator x squared left parenthesis 3 x minus 4 right parenthesis cubed left parenthesis x minus 2 right parenthesis to the power of 4 over denominator left parenthesis x minus 5 right parenthesis to the power of 5 left parenthesis 2 x minus 7 right parenthesis to the power of 6 end fraction less or equal than 0$ is –

2
0
3
4

The correct answer is: 3

Related Questions to study

Set of values of x satisfying the inequality $fraction numerator left parenthesis x minus 3 right parenthesis squared left parenthesis 2 x plus 5 right parenthesis squared left parenthesis x minus 7 right parenthesis over denominator open parentheses x squared plus x plus 1 close parentheses left parenthesis 3 x plus 6 right parenthesis squared end fraction less or equal than 0$ is $left square bracket a comma b right parenthesis union left parenthesis b comma c right square bracket$ then 2a + b + c is equal to

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Number of integral values of x for which the inequality log₁₀ $open parentheses fraction numerator 2 x minus 2007 over denominator x plus 1 end fraction close parentheses$ $less or equal than$ 0 holds true, is

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$x to the power of log subscript 5 invisible function application x end exponent greater than 5$ implies

$x to the power of log subscript 5 invisible function application x end exponent greater than 5$ implies

parallel

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If $open parentheses a to the power of log subscript b end subscript invisible function application x end exponent close parentheses to the power of 2 end exponent$ –5 $x to the power of log subscript b end subscript invisible function application a end exponent$ + 6 = 0 where a > 0, b > 0 & ab $not equal to$ 1. Then the value of x is equal to

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No. of ordered pair satisfying simultaneously the system of equation $2 to the power of square root of x end exponent$ . $2 to the power of square root of y end exponent$ = 256 & log10 $square root of x y end root$ – log10 1.5 = 1 is.

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If a² + 4b² = 12ab, then log (a + 2b) =

If a² + 4b² = 12ab, then log (a + 2b) =

parallel

Given that log_px = α and log_qx = β, then value of log_p_/q x equals-

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parallel

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