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Maths-

General

Easy

Question

The parametric equation of a parabola is x = 4t², y = 8t. The tangents at the points whose parameters are $fraction numerator 1 over denominator 2 end fraction$ and 1 meet on the line -

x = 2
x = 6
y = 2
x + y = 6

The correct answer is: x = 2

Compared to the standard form a = 4.
Point of intersection of tangent is (at₁t₂, a(t₁ + t₂))
i.e., (2, 6) and this lies on x = 2.

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