The two Circles below are concentric, the radius of the larger Circle is 10 cm and that of the smaller Circle is 6cm. What is the length of the chord AB ?

maths-

In the figure x y z=

maths-General

maths-

From the figure $left floor P B R equals$

maths-General

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

Here we used the concept of angle sum property of a triangle. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle EBC is 35 degree.

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if $stack ∣ O A B with _ below$ = 35° then $left floor E B C equals$

chemistry-

About 2 to 5% of gypsum $left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis$ is added to Portland cement. It is just to

chemistry-General

If $sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text then end text sin squared text end text theta$ =

biology

Osmosis is the phenomenon expressed by :

biologyGeneral

If $4 n alpha equals pi comma$ then the numerical value of $tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha$ is equal to

$3 tan to the power of 6 space 10 to the power of ring operator minus 27 tan to the power of 4 space 10 to the power of ring operator plus 33 tan squared space 10 to the power of ring operator space$ =

$sin space 20 to the power of ring operator open parentheses 4 plus sec space 20 to the power of ring operator close parentheses$ =

In the figure $P Q greater than P R comma$ QS and RS are the bisectors of $stack ∣ Q with _ below$ and $stack R with _ below$ respectively then

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

Here we used the concept of linear pair. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle A is 50 degree.

If AB=AC and $A C D equals 115 to the power of ring operator end exponent$ then $stack B with _ below A C equals$

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

Here we used the concept of linear pair and exterior angle property. When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. So here the angle BCD is 110 degrees.

In the figure $A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent$ then ACD=

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =