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Two masses are attached to the pulley as shown in fig., find acceleration of centre of mass

  1. fraction numerator g over denominator 4 end fraction    
  2. fraction numerator negative g over denominator 4 end fraction    
  3. fraction numerator g over denominator 2 end fraction    
  4. fraction numerator negative g over denominator 2 end fraction    

The correct answer is: fraction numerator negative g over denominator 4 end fraction


    Acceleration of the system equals open parentheses fraction numerator 3 m minus m over denominator 3 m plus m end fraction close parentheses   g equals fraction numerator g over denominator 2 end fraction
    therefore Acceleration of C.M.equals fraction numerator negative 3 m cross times fraction numerator g over denominator 2 end fraction plus fraction numerator m g over denominator 2 end fraction over denominator 3 m plus m end fraction
    equals negative fraction numerator m g over denominator 4 m end fraction equals fraction numerator negative g over denominator 4 end fraction.

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