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Maths-

General

Easy

Question

Value of $s i n to the power of 6 space 7 1 half to the power of ring operator plus c o s to the power of 6 space 7 1 half$ is

$\frac{3 \sqrt{3} + 2}{8}$
$\frac{3 \sqrt{3} - 5}{16}$
$\frac{10 + 3 \sqrt{3}}{16}$
$\frac{5 + 3 \sqrt{3}}{16}$

The correct answer is: $fraction numerator 10 plus 3 square root of 3 over denominator 16 end fraction$

$s i n to the power of 6 end exponent invisible function application theta plus c o s to the power of 6 end exponent invisible function application theta equals 1 minus fraction numerator 3 over denominator 4 end fraction s i n to the power of 2 end exponent invisible function application 2 theta comma text put end text theta equals 7 fraction numerator 1 over denominator 2 end fraction$

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