Physics-
General
Easy

Question

A 10 k g mass moves along x-axis. Its acceleration as a function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x equals 0 to x equals 8 blank c m

  1. 8 cross times 10 to the power of negative 2 end exponent blank j o u l e s    
  2. 16 cross times 10 to the power of negative 2 end exponent blank j o u l e s    
  3. 4 cross times 10 to the power of negative 4 end exponent blank j o u l e s    
  4. 1.6 cross times 10 to the power of negative 3 end exponent blank j o u l e s    

The correct answer is: 8 cross times 10 to the power of negative 2 end exponent blank j o u l e s


    Work done = Area covered in between force displacement curve and displacement axis
    = Mass cross timesArea covered in between acceleration-displacement curve and displacement axis
    equals 10 cross times fraction numerator 1 over denominator 2 end fraction open parentheses 8 cross times 10 to the power of negative 2 end exponent cross times 20 cross times 10 to the power of negative 2 end exponent close parentheses equals 8 cross times 10 to the power of negative 2 end exponent J

    Related Questions to study

    General
    physics-

    A mass m slips along the wall of a semispherical surface of radius R. The velocity at the bottom of the surface is

    A mass m slips along the wall of a semispherical surface of radius R. The velocity at the bottom of the surface is

    physics-General
    General
    physics-

    Three forces of magnitudes 6N, 6N and square root of 72 N at a corner of a cube along three sides as shown in figure. Resultant of these forces is

    Three forces of magnitudes 6N, 6N and square root of 72 N at a corner of a cube along three sides as shown in figure. Resultant of these forces is

    physics-General
    General
    physics-

    A man standing on a hill top projects a stone horizontally with speed v subscript 0 end subscript as shown in figure. Taking the coordinate system as given in the figure. The coordinates of the point where the stone will hit the hill surface

    A man standing on a hill top projects a stone horizontally with speed v subscript 0 end subscript as shown in figure. Taking the coordinate system as given in the figure. The coordinates of the point where the stone will hit the hill surface

    physics-General
    parallel
    General
    physics-

    A particle is acted upon by a force F which varies with position x as shown in the figure. If the particle at x equals 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x equals 16 blank m is

    A particle is acted upon by a force F which varies with position x as shown in the figure. If the particle at x equals 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x equals 16 blank m is

    physics-General
    General
    physics-

    A bob of mass m accelerates uniformly from rest to v subscript 1 end subscript in time t subscript 1 end subscript. As a function of t, the instantaneous power delivered to the body is

    A bob of mass m accelerates uniformly from rest to v subscript 1 end subscript in time t subscript 1 end subscript. As a function of t, the instantaneous power delivered to the body is

    physics-General
    General
    physics-

    An aeroplane is flying in a horizontal direction with a velocity 600 k m h to the power of negative 1 end exponent at a height of 1960 m. when it is vertically above the point A on the ground, a body is dropped from it. The body strikes the ground at point B. Calculate the distance A B

    An aeroplane is flying in a horizontal direction with a velocity 600 k m h to the power of negative 1 end exponent at a height of 1960 m. when it is vertically above the point A on the ground, a body is dropped from it. The body strikes the ground at point B. Calculate the distance A B

    physics-General
    parallel
    General
    Maths-

    If the equation fraction numerator x to the power of 2 end exponent over denominator 9 minus k end fraction plus fraction numerator y to the power of 2 end exponent over denominator 5 minus k end fraction equals 1 represents an ellipse then

    If the equation fraction numerator x to the power of 2 end exponent over denominator 9 minus k end fraction plus fraction numerator y to the power of 2 end exponent over denominator 5 minus k end fraction equals 1 represents an ellipse then

    Maths-General
    General
    physics-

    A particle of mass m moving with horizontal speed 6 blank m divided by s e c as shown in figure. If m less than less than M than for one dimensional elastic collision, the speed of lighter particle after collision will be

    A particle of mass m moving with horizontal speed 6 blank m divided by s e c as shown in figure. If m less than less than M than for one dimensional elastic collision, the speed of lighter particle after collision will be

    physics-General
    General
    Physics-

    A particle of mass m attracted with a string of length l is just revolving on the vertical circle without slacking of the string. If v subscript A end subscript comma v subscript B end subscript and v subscript D end subscript are speed at position A comma B and D then

    A particle of mass m attracted with a string of length l is just revolving on the vertical circle without slacking of the string. If v subscript A end subscript comma v subscript B end subscript and v subscript D end subscript are speed at position A comma B and D then

    Physics-General
    parallel
    General
    physics-

    A simple pendulum is released from A as shown. If m and l represent the mass of the bob and length of the pendulum, the gain in kinetic energy at B is

    A simple pendulum is released from A as shown. If m and l represent the mass of the bob and length of the pendulum, the gain in kinetic energy at B is

    physics-General
    General
    Maths-

    P(θ) and D space open parentheses theta plus pi over 2 close parentheses are the pts. on the ellipse b x to the power of 2 end exponent plus a to the power of 2 end exponent y to the power of 2 end exponent equals a to the power of 2 end exponent b to the power of 2 end exponent then C P to the power of 2 end exponent plus C D to the power of 2 end exponent equals

    P(θ) and D space open parentheses theta plus pi over 2 close parentheses are the pts. on the ellipse b x to the power of 2 end exponent plus a to the power of 2 end exponent y to the power of 2 end exponent equals a to the power of 2 end exponent b to the power of 2 end exponent then C P to the power of 2 end exponent plus C D to the power of 2 end exponent equals

    Maths-General
    General
    physics-

    A ball of mass 0.2 blank k g rests on a vertical post of height 5 blank m. A bullet of mass 0.01 blank k g, travelling with a velocity V blank m divided by s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 blank mand the bullet at a distance of 100 blank mfrom the foot of the post. The initial velocity V of the bullet is

    A ball of mass 0.2 blank k g rests on a vertical post of height 5 blank m. A bullet of mass 0.01 blank k g, travelling with a velocity V blank m divided by s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 blank mand the bullet at a distance of 100 blank mfrom the foot of the post. The initial velocity V of the bullet is

    physics-General
    parallel
    General
    physics-

    A particle P is sliding down a frictionless hemispherical bowl. It passes the point Aat t equals 0. At this instant of time, the horizontal component of its velocity v. A bead Q of the same mass as P is ejected from A to t equals 0 along the horizontal string A B (see figure) with the speed v. Friction between the bead and the string may be neglected. Let t subscript p end subscript and t subscript Q end subscript be the respective time taken by P and Q to reach the point B. Then

    A particle P is sliding down a frictionless hemispherical bowl. It passes the point Aat t equals 0. At this instant of time, the horizontal component of its velocity v. A bead Q of the same mass as P is ejected from A to t equals 0 along the horizontal string A B (see figure) with the speed v. Friction between the bead and the string may be neglected. Let t subscript p end subscript and t subscript Q end subscript be the respective time taken by P and Q to reach the point B. Then

    physics-General
    General
    Maths-

    If the chords of contact of P space open parentheses x subscript 1 comma y subscript 1 close parentheses and Q space open parentheses x subscript 2 comma y subscript 2 close parentheses w.r.t the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 are at right angle then fraction numerator x subscript 1 end subscript x subscript 2 end subscript over denominator y subscript 1 end subscript y subscript 2 end subscript end fraction equals

    If the chords of contact of P space open parentheses x subscript 1 comma y subscript 1 close parentheses and Q space open parentheses x subscript 2 comma y subscript 2 close parentheses w.r.t the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 are at right angle then fraction numerator x subscript 1 end subscript x subscript 2 end subscript over denominator y subscript 1 end subscript y subscript 2 end subscript end fraction equals

    Maths-General
    General
    Maths-

    The area of an ellipse is 8π sq. units dist. between the foci is 4 square root of 3 then e=

    The area of an ellipse is 8π sq. units dist. between the foci is 4 square root of 3 then e=

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.