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Physics-

General

Easy

Question

A simple pendulum is released from $A$ as shown. If $m$ and $l$ represent the mass of the bob and length of the pendulum, the gain in kinetic energy at $B$ is

$\frac{m g l}{2}$
$\frac{m g l}{\sqrt{2}}$
$\frac{\sqrt{3}}{2} m g l$
$\frac{\sqrt{2}}{3} m g l$

The correct answer is: $fraction numerator square root of 3 over denominator 2 end fraction m g l$

Vertical height $equals h equals l cos invisible function application 30 degree$
Loss of potential energy $equals m g h$

$equals m g l cos invisible function application 30 degree equals fraction numerator square root of 3 over denominator 2 end fraction m g l$
$therefore$ Kinetic energy gained $equals fraction numerator square root of 3 over denominator 2 end fraction m g l$

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