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Physics-

General

Easy

Question

A beaker containing a liquid of density ρ moves up with an acceleration a. The pressure due to liquid at a depth h below the free surface of liquid is..

hrg
$h ρ (g - a)$
$h ρ (g + a)$
$2 h ρ g (\frac{g + a}{g - a})$

The correct answer is: $h rho left parenthesis g plus a right parenthesis$

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