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A block placed on a rough inclined plane of inclination open parentheses theta equals 30 to the power of ring operator end exponent close parentheses can just be pushed upwards by applying a force "F" as shown. If the angle of inclination of the inclined plane is increased to open parentheses theta equals 60 to the power of ring operator end exponent close parentheses, the same block can just be prevented from sliding down by application of a force of same magnitude. The coefficient of friction between the block and the inclined plane is

  1. fraction numerator square root of 3 plus 1 over denominator square root of 3 minus 1 end fraction    
  2. fraction numerator 2 square root of 3 minus 1 over denominator square root of 3 plus 1 end fraction    
  3. fraction numerator square root of 3 minus 1 over denominator square root of 3 plus 1 end fraction    
  4. None of these    

The correct answer is: fraction numerator square root of 3 minus 1 over denominator square root of 3 plus 1 end fraction

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