Physics-
General
Easy

Question

A bob of mass m is suspended by a string from a train of mass M, free to move on a horizontal surface The bob is given a horizontal velocity V0 The maximum height attained by the bob is

  1. fraction numerator V subscript 0 end subscript superscript 2 end superscript over denominator 2 g end fraction open parentheses fraction numerator M plus m over denominator M end fraction close parentheses    
  2. fraction numerator V subscript 0 end subscript superscript 2 end superscript m over denominator 2 g M end fraction    
  3. fraction numerator V subscript 0 end subscript superscript 2 end superscript M over denominator 2 g left parenthesis M plus m right parenthesis end fraction    
  4. fraction numerator V subscript 0 end subscript superscript 2 end superscript over denominator 2 g end fraction    

The correct answer is: fraction numerator V subscript 0 end subscript superscript 2 end superscript M over denominator 2 g left parenthesis M plus m right parenthesis end fraction


    Apply COM, mV0 = (M + m)V2
    Apply work energy theorem
    DKE = W. D. by all forces
    fraction numerator 1 over denominator 2 end fraction left parenthesis m plus M right parenthesis V subscript 2 end subscript superscript 2 end superscript minus fraction numerator 1 over denominator 2 end fraction m V subscript 0 end subscript superscript 2 end superscript equals negative m g h
    h equals fraction numerator V subscript 0 end subscript superscript 2 end superscript M over denominator 2 g left parenthesis M plus m right parenthesis end fraction

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