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Physics-

General

Easy

Question

A body begins to walk eastward along a street in front of his house and the graph of his position from home is shown in the following figure. His average speed for the whole time interval is equal to

$8 m / m i n$
$6 m / m i n$
$\frac{8}{3} m / m i n$
$2 m / m i n$

The correct answer is: $6 blank m divided by m i n$

Average speed is the ratio of distance to time taken
Distance travelled from $0$ to $5 s equals 40 blank m$
Distance travelled from $5$ to $10 s equals 0 blank m$
Distance travelled from $10$ to $15 s equals 60 blank m$
Distance travelled from $15$ to $20 s equals 20$
So, total distance $equals 40 plus 0 plus 60 plus 20 equals 120 blank m$
Total time taken $equals 20 blank m i n u t e s$
Hence, average speed
$equals fraction numerator d i s t a n c e blank t r a v e l l e d blank left parenthesis m right parenthesis over denominator t i m e blank left parenthesis m i n right parenthesis end fraction equals fraction numerator 120 over denominator 20 end fraction equals 6 blank m divided by m i n$

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