Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A conducting ring is placed around the core of an electromagnet as shown in fig. When key K is pressed, the ring

Remain stationary
Is attracted towards the electromagnet
Jumps out of the core
None of the above

The correct answer is: Jumps out of the core

When key k is pressed, current through the electromagnet start increasing i.e. flux linked with ring increases which produces repulsion effect

Related Questions to study

Shown in the figure is a circular loop of radius r and resistance R. A variable magnetic field of induction $B equals B subscript 0 end subscript e to the power of negative t end exponent$ is established inside the coil. If the key (K) is closed, the electrical power developed right after closing the switch is equal to

Shown in the figure is a circular loop of radius r and resistance R. A variable magnetic field of induction $B equals B subscript 0 end subscript e to the power of negative t end exponent$ is established inside the coil. If the key (K) is closed, the electrical power developed right after closing the switch is equal to

physics-General

The resistance in the following circuit is increased at a particular instant. At this instant the value of resistance is 10W. The current in the circuit will be now

The resistance in the following circuit is increased at a particular instant. At this instant the value of resistance is 10W. The current in the circuit will be now

physics-General

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 2 m/s in a uniform magnetic field $B equals 4.0 T$ directed into the paper. A capacitor of capacity C = 10 mF is connected as shown in figure. Then

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 2 m/s in a uniform magnetic field $B equals 4.0 T$ directed into the paper. A capacitor of capacity C = 10 mF is connected as shown in figure. Then

physics-General

parallel

Let f(x) = $open parentheses fraction numerator open vertical bar sin invisible function application x rightwards arrow over short leftwards arrow close vertical bar over denominator cos invisible function application x end fraction plus fraction numerator sin invisible function application x over denominator open vertical bar cos invisible function application x close vertical bar end fraction close parentheses$
Assertion (A): Fundamental period of f(x) is 2 $straight pi$
Reason (R) : period of sin x and cos x is 2 $straight pi$

Let f(x) = $open parentheses fraction numerator open vertical bar sin invisible function application x rightwards arrow over short leftwards arrow close vertical bar over denominator cos invisible function application x end fraction plus fraction numerator sin invisible function application x over denominator open vertical bar cos invisible function application x close vertical bar end fraction close parentheses$
Assertion (A): Fundamental period of f(x) is 2 $straight pi$
Reason (R) : period of sin x and cos x is 2 $straight pi$

If (x₁,y₁) and (x₂, y₂) and ends of a focal chord of the parabola $y to the power of 2 end exponent$ = 4ax, then square of G.M. of x₁and x₂ is-

If (x₁,y₁) and (x₂, y₂) and ends of a focal chord of the parabola $y to the power of 2 end exponent$ = 4ax, then square of G.M. of x₁and x₂ is-

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m², as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m², as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is

physics-General

parallel

A square metallic wire loop of side 0.1 m and resistance of 1W is moved with a constant velocity in a magnetic field of 2 wb/m² as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

A square metallic wire loop of side 0.1 m and resistance of 1W is moved with a constant velocity in a magnetic field of 2 wb/m² as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

physics-General

A conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced current in wires AB and CD are

A conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced current in wires AB and CD are

physics-General

As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with $B equals 0.15 t e s l a.$ If the resistance is $3 capital omega$ , force needed to move the rod as indicated with a constant speed of $2 m divided by s e c$ is

As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with $B equals 0.15 t e s l a.$ If the resistance is $3 capital omega$ , force needed to move the rod as indicated with a constant speed of $2 m divided by s e c$ is

physics-General

parallel

As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current $I subscript P end subscript$ flows in P (as seen by E) and an induced current $I subscript Q subscript 1 end subscript end subscript$ flows in Q. The switch remains closed for a long time. When S is opened, a current $I subscript Q subscript 2 end subscript end subscript$ flows in Q. Then the directions of $I subscript Q subscript 1 end subscript end subscript$ and $I subscript Q subscript 2 end subscript end subscript$ (as seen by E) are

As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current $I subscript P end subscript$ flows in P (as seen by E) and an induced current $I subscript Q subscript 1 end subscript end subscript$ flows in Q. The switch remains closed for a long time. When S is opened, a current $I subscript Q subscript 2 end subscript end subscript$ flows in Q. Then the directions of $I subscript Q subscript 1 end subscript end subscript$ and $I subscript Q subscript 2 end subscript end subscript$ (as seen by E) are

physics-General

A particle moves along a line by $s equals t to the power of 3 end exponent minus 9 t to the power of 2 end exponent plus 24 t$ then S is decreasing when t $element of$

A particle moves along a line by $s equals t to the power of 3 end exponent minus 9 t to the power of 2 end exponent plus 24 t$ then S is decreasing when t $element of$

Assertion: f(x) = ln $open vertical bar fraction numerator 1 plus tan invisible function application x over denominator 1 minus tan invisible function application x end fraction close vertical bar$ is an odd function.
Reason: Let f be a function with domain D such that
i) x $element of$ D $rightwards double arrow$ – x $element of$ D
ii) f(–x) = – f(x) and
iii) f (0) = 0 or f (0) is not defined
Then the function f(x) is an odd function

Assertion: f(x) = ln $open vertical bar fraction numerator 1 plus tan invisible function application x over denominator 1 minus tan invisible function application x end fraction close vertical bar$ is an odd function.
Reason: Let f be a function with domain D such that
i) x $element of$ D $rightwards double arrow$ – x $element of$ D
ii) f(–x) = – f(x) and
iii) f (0) = 0 or f (0) is not defined
Then the function f(x) is an odd function

parallel

A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $Error converting from MathML to accessible text.$ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $Error converting from MathML to accessible text.$ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

physics-General

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

physics-General

Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be

Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be

physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.