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Physics-

General

Easy

Question

A cubic container is filled with a liquid whose refractive index increases linearly from top to bottom. Which of the following represents the path of a ray of light inside the liquid?

The correct answer is:

Related Questions to study

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index m . P is a small object at a height h above the mirror. An observer O, vertically above P, outside the liquid, observes P and its image in the mirror. The apparent distance between these two will be

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index m . P is a small object at a height h above the mirror. An observer O, vertically above P, outside the liquid, observes P and its image in the mirror. The apparent distance between these two will be

physics-General

A ray of light travels in the way as shown in the figure. After passing through water, the ray grazes along the water air interface. The value of m_g interms of ‘i’ is $open parentheses mu subscript w end subscript equals 4 divided by 3 close parentheses$

A ray of light travels in the way as shown in the figure. After passing through water, the ray grazes along the water air interface. The value of m_g interms of ‘i’ is $open parentheses mu subscript w end subscript equals 4 divided by 3 close parentheses$

physics-General

A reflecting surface is represented by the equation $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$ . A ray travelling in negative x-direction is directed towards positive y-direction after reflection from the surface at point P. Then co-ordinates of point P are

A reflecting surface is represented by the equation $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$ . A ray travelling in negative x-direction is directed towards positive y-direction after reflection from the surface at point P. Then co-ordinates of point P are

physics-General

parallel

If $3 Tan to the power of 4 space alpha minus 10 Tan squared space alpha plus 3 equals 0$ then principal values of ' $alpha$ ' are

If $3 Tan to the power of 4 space alpha minus 10 Tan squared space alpha plus 3 equals 0$ then principal values of ' $alpha$ ' are

If $Sin space open parentheses fraction numerator pi Cot space theta over denominator 4 end fraction close parentheses equals Cos space open parentheses fraction numerator pi Tan space theta over denominator 4 end fraction close parentheses$ and $theta$ is in the first quadrant then $theta$ =....

If $Sin space open parentheses fraction numerator pi Cot space theta over denominator 4 end fraction close parentheses equals Cos space open parentheses fraction numerator pi Tan space theta over denominator 4 end fraction close parentheses$ and $theta$ is in the first quadrant then $theta$ =....

If $Tan squared space theta equals square root of 3 plus left parenthesis square root of 3 minus 1 right parenthesis Tan space theta$ and $theta$ lies in $open parentheses negative pi over 2 comma pi over 2 close parentheses$ then $theta$ =

If $Tan squared space theta equals square root of 3 plus left parenthesis square root of 3 minus 1 right parenthesis Tan space theta$ and $theta$ lies in $open parentheses negative pi over 2 comma pi over 2 close parentheses$ then $theta$ =

parallel

If , then $Tan space theta plus Sec space theta equals square root of 3$ he principal value of $open parentheses theta plus pi over 6 close parentheses$ is

If , then $Tan space theta plus Sec space theta equals square root of 3$ he principal value of $open parentheses theta plus pi over 6 close parentheses$ is

In a $straight triangle A B C comma sin to the power of 4 invisible function application A plus sin to the power of 4 invisible function application B plus sin to the power of 4 invisible function application C equals$

In a $straight triangle A B C comma sin to the power of 4 invisible function application A plus sin to the power of 4 invisible function application B plus sin to the power of 4 invisible function application C equals$

If $4 cos squared space theta equals 3 text then end text theta equals negative midline horizontal ellipsis minus negative$

If $4 cos squared space theta equals 3 text then end text theta equals negative midline horizontal ellipsis minus negative$

parallel

The value of $sum from k equals 1 to 100 of sin space left parenthesis k x right parenthesis cos space left parenthesis 101 minus k right parenthesis x$ is equal to

The value of $sum from k equals 1 to 100 of sin space left parenthesis k x right parenthesis cos space left parenthesis 101 minus k right parenthesis x$ is equal to

If $alpha comma beta comma gamma text are acute angles and end text cos text end text theta equals sin space beta divided by sin space alpha comma cos space ϕ equals sin space gamma divided by sin invisible function application alpha$ and $cos space left parenthesis theta minus ϕ right parenthesis equals sin space beta sin space gamma$ then the value of $tan squared space alpha minus tan squared space beta minus tan squared space gamma$ is equal to

If $alpha comma beta comma gamma text are acute angles and end text cos text end text theta equals sin space beta divided by sin space alpha comma cos space ϕ equals sin space gamma divided by sin invisible function application alpha$ and $cos space left parenthesis theta minus ϕ right parenthesis equals sin space beta sin space gamma$ then the value of $tan squared space alpha minus tan squared space beta minus tan squared space gamma$ is equal to

If $x sin space a plus y sin space 2 a plus z sin space 3 a equals sin space 4 a x sin space b plus y sin space 2 b plus z sin space 3 b equals sin space 4 b comma x sin space c plus y sin space 2 c plus z sin space 3 c equals sin space 4 c$ Then the roots of the equation $t cubed minus open parentheses z over 2 close parentheses t squared minus open parentheses fraction numerator y plus z over denominator 4 end fraction close parentheses t plus open parentheses fraction numerator z minus x over denominator 8 end fraction close parentheses equals 0 comma a comma b comma c not equal to n pi$ are

If $x sin space a plus y sin space 2 a plus z sin space 3 a equals sin space 4 a x sin space b plus y sin space 2 b plus z sin space 3 b equals sin space 4 b comma x sin space c plus y sin space 2 c plus z sin space 3 c equals sin space 4 c$ Then the roots of the equation $t cubed minus open parentheses z over 2 close parentheses t squared minus open parentheses fraction numerator y plus z over denominator 4 end fraction close parentheses t plus open parentheses fraction numerator z minus x over denominator 8 end fraction close parentheses equals 0 comma a comma b comma c not equal to n pi$ are

parallel

If $equals fraction numerator 2 pi over denominator 7 end fraction$ ,then tan $alpha tan invisible function application 2 alpha plus tan invisible function application 2 alpha tan invisible function application 4 alpha plus tan invisible function application 4 alpha tan invisible function application alpha equals$

If $equals fraction numerator 2 pi over denominator 7 end fraction$ ,then tan $alpha tan invisible function application 2 alpha plus tan invisible function application 2 alpha tan invisible function application 4 alpha plus tan invisible function application 4 alpha tan invisible function application alpha equals$

If the mapping $f left parenthesis x right parenthesis equals a x plus b comma a less than 0$ maps [-1,1] onto [0,2] then for all values of $theta$ , $A equals cos squared space theta plus sin to the power of 4 space theta$ is such that

If the mapping $f left parenthesis x right parenthesis equals a x plus b comma a less than 0$ maps [-1,1] onto [0,2] then for all values of $theta$ , $A equals cos squared space theta plus sin to the power of 4 space theta$ is such that

If $fraction numerator sec to the power of 8 space theta over denominator a end fraction plus fraction numerator tan to the power of 8 begin display style space end style theta over denominator b end fraction equals fraction numerator 1 over denominator a plus b end fraction$ then

If $fraction numerator sec to the power of 8 space theta over denominator a end fraction plus fraction numerator tan to the power of 8 begin display style space end style theta over denominator b end fraction equals fraction numerator 1 over denominator a plus b end fraction$ then

parallel

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