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A diode is connected to 220 V (rms) ac in series with a capacitor as shown in figure. The voltage across the capacitor is

220 V
110 V
311.1 V
$\frac{220}{\sqrt{2}} V$

The correct answer is: $fraction numerator 220 over denominator square root of 2 end fraction V$

The diode D will conduct for positive half cycle of a.c. supply because this is forward biased. For negative half cycle of a.c. supply, this is reverse biased and does not conduct. So output would be half wave rectified and for half wave rectified out put
$V subscript r m s end subscript equals fraction numerator V subscript 0 end subscript over denominator 2 end fraction equals fraction numerator 200 square root of 2 over denominator 2 end fraction equals fraction numerator 200 over denominator square root of 2 end fraction$

In which of the following circuit is the current maximum just after the switch S is closed

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maths-

Range of function f(x) = $fraction numerator x squared plus 2 x plus 3 over denominator x end fraction comma x element of R$ is given by

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physics-

Find V_AB

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General

physics-

The circuit shown in following figure contains two diode $D subscript 1 end subscript$ and $D subscript 1 end subscript$ each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

physics-General

General

physics-

In the following circuits PN-junction diodes D₁, D₂ and D₃ are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be

i) – 10 V, – 5V (ii) – 5V, – 10 V
iii) – 4V, – 12V

physics-General

General

physics-

In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop $V subscript A B end subscript left parenthesis t right parenthesis$ across the resistance R is

physics-General

General

physics-

The junction diode in the following circuit requires a minimum current of 1 mA to be above the knee point (0.7 V) of its I-V characteristic curve. The voltage across the diode is independent of current above the knee point. If V_B = 5 V, then the maximum value of R so that the voltage is above the knee point, will be

physics-General

General

physics-

In semiconductor the concentrations of electrons and holes are 8 ×10¹⁸/m³ and 5 × 10¹⁸/m respectively. If the mobilities of electrons and hole are 2.3 m²/volt-sec and 0.01 m²/volt-sec respectively, then semiconductor is

physics-General

General

physics-

In the following common emitter configuration, an NPN transistor with current gain $beta equals 100$ is used. The output voltage of the amplifier will be

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Maths-

The period of f(x) = [sin 5x] + |cos 6x| is -

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physics-

The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milliwatts. What should be the value of the resistor R, connected in series with the diode for obtaining maximum current

physics-General

General

physics-

Current in the circuit will be

physics-General

General

physics-

In the circuit, if the forward voltage drop for the diode is 0.5V, the current will be

physics-General

General

physics-

A 2V battery is connected across the points A and B as shown in the figure given below. Assuming that the resistance of each diode is zero in forward bias and infinity in reverse bias, the current supplied by the battery when its positive terminal is connected to A is

physics-General

General

Maths-

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –

the m-n theorem states that
(m + n) cot θ = m cot α – n cot ß
this gives us the cotangent of the angle CDA which is further used in the sine rule to find the length of AC

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –

Maths-General

the m-n theorem states that
(m + n) cot θ = m cot α – n cot ß
this gives us the cotangent of the angle CDA which is further used in the sine rule to find the length of AC

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A diode is connected to 220 V (rms) ac in series with a capacitor as shown in figure. The voltage across the capacitor is

220 V 110 V 311.1 V

The correct answer is:

The diode D will conduct for positive half cycle of a.c. supply because this is forward biased. For negative half cycle of a.c. supply, this is reverse biased and does not conduct. So output would be half wave rectified and for half wave rectified out put

Related Questions to study

In which of the following circuit is the current maximum just after the switch S is closed

In which of the following circuit is the current maximum just after the switch S is closed

Range of function f(x) = is given by

Range of function f(x) = is given by

Find VAB

Find VAB

The circuit shown in following figure contains two diode and each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

The circuit shown in following figure contains two diode and each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

In the following circuits PN-junction diodes D1, D2 and D3 are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will bei) – 10 V, – 5V (ii) – 5V, – 10 Viii) – 4V, – 12V

In the following circuits PN-junction diodes D1, D2 and D3 are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will bei) – 10 V, – 5V (ii) – 5V, – 10 Viii) – 4V, – 12V

In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop across the resistance R is

In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop across the resistance R is

In semiconductor the concentrations of electrons and holes are 8 ×1018/m3 and 5 × 1018/m respectively. If the mobilities of electrons and hole are 2.3 m2/volt-sec and 0.01 m2/volt-sec respectively, then semiconductor is

In semiconductor the concentrations of electrons and holes are 8 ×1018/m3 and 5 × 1018/m respectively. If the mobilities of electrons and hole are 2.3 m2/volt-sec and 0.01 m2/volt-sec respectively, then semiconductor is

In the following common emitter configuration, an NPN transistor with current gain is used. The output voltage of the amplifier will be

In the following common emitter configuration, an NPN transistor with current gain is used. The output voltage of the amplifier will be

The period of f(x) = [sin 5x] + |cos 6x| is -

The period of f(x) = [sin 5x] + |cos 6x| is -

The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milliwatts. What should be the value of the resistor R, connected in series with the diode for obtaining maximum current

The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milliwatts. What should be the value of the resistor R, connected in series with the diode for obtaining maximum current

Current in the circuit will be

Current in the circuit will be

In the circuit, if the forward voltage drop for the diode is 0.5V, the current will be

In the circuit, if the forward voltage drop for the diode is 0.5V, the current will be

A 2V battery is connected across the points A and B as shown in the figure given below. Assuming that the resistance of each diode is zero in forward bias and infinity in reverse bias, the current supplied by the battery when its positive terminal is connected to A is

A 2V battery is connected across the points A and B as shown in the figure given below. Assuming that the resistance of each diode is zero in forward bias and infinity in reverse bias, the current supplied by the battery when its positive terminal is connected to A is

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and = 60º. Then the length of AC is –

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and = 60º. Then the length of AC is –

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220 V
110 V
311.1 V
$\frac{220}{\sqrt{2}} V$

The correct answer is: $fraction numerator 220 over denominator square root of 2 end fraction V$

Range of function f(x) = $fraction numerator x squared plus 2 x plus 3 over denominator x end fraction comma x element of R$ is given by

Range of function f(x) = $fraction numerator x squared plus 2 x plus 3 over denominator x end fraction comma x element of R$ is given by

Find V_AB

Find V_AB

The circuit shown in following figure contains two diode $D subscript 1 end subscript$ and $D subscript 1 end subscript$ each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

The circuit shown in following figure contains two diode $D subscript 1 end subscript$ and $D subscript 1 end subscript$ each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

In the following circuits PN-junction diodes D₁, D₂ and D₃ are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be

i) – 10 V, – 5V (ii) – 5V, – 10 V
iii) – 4V, – 12V

In the following circuits PN-junction diodes D₁, D₂ and D₃ are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be

i) – 10 V, – 5V (ii) – 5V, – 10 V
iii) – 4V, – 12V

In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop $V subscript A B end subscript left parenthesis t right parenthesis$ across the resistance R is

In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop $V subscript A B end subscript left parenthesis t right parenthesis$ across the resistance R is

In semiconductor the concentrations of electrons and holes are 8 ×10¹⁸/m³ and 5 × 10¹⁸/m respectively. If the mobilities of electrons and hole are 2.3 m²/volt-sec and 0.01 m²/volt-sec respectively, then semiconductor is

In semiconductor the concentrations of electrons and holes are 8 ×10¹⁸/m³ and 5 × 10¹⁸/m respectively. If the mobilities of electrons and hole are 2.3 m²/volt-sec and 0.01 m²/volt-sec respectively, then semiconductor is

In the following common emitter configuration, an NPN transistor with current gain $beta equals 100$ is used. The output voltage of the amplifier will be

In the following common emitter configuration, an NPN transistor with current gain $beta equals 100$ is used. The output voltage of the amplifier will be

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –