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Physics-

General

Easy

Question

A homogeneous solid cylinder of length L (L < H/2), cross–sectional area A/5 is immersed such that it floats with its axis vertical at the liquid–liquid interface with length L/4 in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure $P subscript 0 end subscript$ . Then, density D of solid is given by :–

$\frac{5}{4} d$
$\frac{4}{5} d$
4d
d/5

The correct answer is: $fraction numerator 5 over denominator 4 end fraction d$

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