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Physics-

General

Easy

Question

A solid uniform ball having volume V and density $rho$ floats at the interface of two unmixable liquids as shown in figure. The densities of the upper and the lower liquids are $rho subscript 1 end subscript$ and $rho subscript 2 end subscript$ respectively, such that $rho subscript 1 end subscript less than rho less than rho subscript 2 end subscript$ . What fraction of the volume of the ball will be in the lower liquid :–

$\frac{ρ - ρ_{2}}{ρ_{1} - ρ_{2}}$
$\frac{ρ_{1}}{ρ_{1} - ρ_{2}}$
$\frac{ρ_{1} - ρ}{ρ_{1} - ρ_{2}}$
$\frac{ρ_{1} - ρ_{2}}{ρ_{2}}$

The correct answer is: $fraction numerator rho subscript 1 end subscript minus rho over denominator rho subscript 1 end subscript minus rho subscript 2 end subscript end fraction$

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