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Physics-

General

Easy

Question

A horizontal force $F equals 20 N$ is applied on a block of mass 2 kg placed on rough inclined plane with coefficient of friction $mu equals 0.2$ as shown, then the acceleration of block is $open parentheses tan invisible function application 3 7 degree equals fraction numerator 3 over denominator 4 end fraction comma g equals 10 m divided by s to the power of 2 end exponent close parentheses$

$2 m/ s^{2}$
$1 m / s^{2}$
$z e r o$
$1.5 m / s^{2}$

The correct answer is: $z e r o$

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$e element of$ $open parentheses negative fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction comma fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses$
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