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Physics-

General

Easy

Question

Consider the system shown in figure. The wall is smooth, but the surface of blocks A and B in
contact are rough. The friction on B due to A in equilibrium is

Upward
Downward
Zero
The system can not remain in equilibrium

The correct answer is: The system can not remain in equilibrium

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Two genes R and Y located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F₂ segregation will show

Two genes R and Y located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F₂ segregation will show

Assertion : The locus of the centre of a circle which touches the circles $open vertical bar z minus z subscript 1 end subscript close vertical bar equals a$ and $open vertical bar z minus z subscript 2 end subscript close vertical bar equals b$ externally (z, $z subscript 1 end subscript$ and $z subscript 2 end subscript$ are complex numbers) will be hyperbola
Reason : $open vertical bar z minus z subscript 1 end subscript close vertical bar minus open vertical bar z minus z subscript 2 end subscript close vertical bar less than open vertical bar z subscript 2 end subscript minus z subscript 1 end subscript close vertical bar$
$not stretchy rightwards double arrow$ z lies on hyperbola

Assertion : The locus of the centre of a circle which touches the circles $open vertical bar z minus z subscript 1 end subscript close vertical bar equals a$ and $open vertical bar z minus z subscript 2 end subscript close vertical bar equals b$ externally (z, $z subscript 1 end subscript$ and $z subscript 2 end subscript$ are complex numbers) will be hyperbola
Reason : $open vertical bar z minus z subscript 1 end subscript close vertical bar minus open vertical bar z minus z subscript 2 end subscript close vertical bar less than open vertical bar z subscript 2 end subscript minus z subscript 1 end subscript close vertical bar$
$not stretchy rightwards double arrow$ z lies on hyperbola

Assertion : Consider an ellipse having its foci at A( $z subscript 1 end subscript$ ) and B( $z subscript 2 end subscript$ ) in the Argand plane. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of the ellipse then
$e element of$ $open parentheses negative fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction comma fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses$
Reason : If $Z subscript 0 end subscript$ is the point interior to curve $open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda rightwards double arrow open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda$

Assertion : Consider an ellipse having its foci at A( $z subscript 1 end subscript$ ) and B( $z subscript 2 end subscript$ ) in the Argand plane. If the eccentricity of the ellipse be 'e' and it is known that origin is an interior point of the ellipse then
$e element of$ $open parentheses negative fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction comma fraction numerator vertical line z subscript 1 end subscript plus z subscript 2 end subscript vertical line over denominator vertical line z subscript 1 end subscript vertical line plus vertical line z subscript 2 end subscript vertical line end fraction close parentheses$
Reason : If $Z subscript 0 end subscript$ is the point interior to curve $open vertical bar z minus z subscript 1 end subscript close vertical bar plus open vertical bar z minus z subscript 2 end subscript close vertical bar equals lambda rightwards double arrow open vertical bar z subscript 0 end subscript minus z subscript 1 end subscript close vertical bar plus open vertical bar z subscript 0 end subscript minus z subscript 2 end subscript close vertical bar less than lambda$

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If $alpha$ and $beta$ are different complex numbers with | $beta$ | = 1, then $open vertical bar fraction numerator beta minus alpha over denominator 1 minus stack alpha with ̄ on top beta end fraction close vertical bar$ is equal to

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A block of mass $m subscript 1 end subscript$ rests on a rough horizontal plane relative to which the coefficient of friction is $mu.$ . A light string attached to the body passes over a light pulley and carries at its other end a mass $m subscript 2 end subscript$ and the system just begins to move. The value of $mu$ .

A block of mass $m subscript 1 end subscript$ rests on a rough horizontal plane relative to which the coefficient of friction is $mu.$ . A light string attached to the body passes over a light pulley and carries at its other end a mass $m subscript 2 end subscript$ and the system just begins to move. The value of $mu$ .

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If $alpha$ and $beta$ are different complex numbers with
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If $alpha$ and $beta$ are different complex numbers with
| $beta$ | = 1, then $open vertical bar fraction numerator beta minus alpha over denominator 1 minus alpha beta end fraction close vertical bar$ is equal to

Let z₁ and z₂ be complex numbers, then $open vertical bar z subscript 1 end subscript plus z subscript 2 end subscript close vertical bar to the power of 2 end exponent plus open vertical bar z subscript 1 end subscript minus z subscript 2 end subscript close vertical bar to the power of 2 end exponent$ is equal to

Let z₁ and z₂ be complex numbers, then $open vertical bar z subscript 1 end subscript plus z subscript 2 end subscript close vertical bar to the power of 2 end exponent plus open vertical bar z subscript 1 end subscript minus z subscript 2 end subscript close vertical bar to the power of 2 end exponent$ is equal to

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For all complex number z₁, z₂ satisfying $open vertical bar z subscript 1 end subscript close vertical bar$ = 12 and $open vertical bar z subscript 2 end subscript minus 3 minus 4 i close vertical bar equals 5$ , the minimum value of $open vertical bar z subscript 1 end subscript minus z subscript 2 end subscript close vertical bar$ is -

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physics-General

Blocks A and B in the figure are connected by a bar of negligible weight. If mass of A and B are 170 kg each and $mu subscript A end subscript equals 0.2$ and $mu subscript B end subscript equals 0.4 comma$ where $mu subscript A end subscript$ and $mu subscript B end subscript$ are the coefficient of limiting friction between blocks and plane, calculate the force in the bar. $open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses$

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