Physics-
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Question

A mass M is attached to a horizontal spring of force constant k fixed on one side to a rigid support as shown in figure. The mass oscillates on a frictionless surface with time period T and amplitude A . When the mass is in equilibrium position. Another mass m is gently placed on it. What will be the new amplitude of oscillations?

  1. A square root of open parentheses fraction numerator M over denominator M minus m end fraction close parentheses end root    
  2. A square root of open parentheses fraction numerator M minus m over denominator M end fraction close parentheses end root    
  3. A square root of open parentheses fraction numerator M over denominator M plus m end fraction close parentheses end root    
  4. A square root of open parentheses fraction numerator M plus m over denominator M end fraction close parentheses end root    

The correct answer is: A square root of open parentheses fraction numerator M over denominator M plus m end fraction close parentheses end root


    When a mass m is placed on massM, the new system is of massequals left parenthesis M plus m right parenthesis, attached to the spring. New time period of oscillation,
    T to the power of ´ end exponent equals 2 pi square root of fraction numerator M plus m over denominator k end fraction end root
    T equals 2 pi square root of fraction numerator M over denominator k end fraction end root
    Let v equalsvelocity of the mass M while passing through the mean position.
    v to the power of ´ end exponent equalsVelocity of the massleft parenthesis M plus m right parenthesis, while passing through the mean position.
    According to law of conservation of linear momentum M v equals open parentheses M plus m close parentheses v to the power of ´ end exponent
    At mean position, v equals A blank omega and v to the power of ´ end exponent equals A to the power of ´ end exponent omega to the power of ´ end exponent
    therefore blank M A omega equals open parentheses m plus m close parentheses A to the power of ´ end exponent omega to the power of blank
    or A to the power of ´ end exponent equals open parentheses fraction numerator M over denominator M plus m end fraction close parentheses fraction numerator omega over denominator omega end fraction comma A equals fraction numerator M over denominator M plus m end fraction cross times fraction numerator T to the power of ´ end exponent over denominator T end fraction cross times A
    equals open parentheses fraction numerator M over denominator M plus m end fraction close parentheses cross times square root of fraction numerator M plus m over denominator M end fraction end root cross times A
    equals A square root of fraction numerator M over denominator M plus m end fraction end root

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