Physics-
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Question

A uniform rod of length L and mass M is pivoted at the centre. Its two ends are attached to two springs of equal spring constant k. The springs are fixed to rigid supports as shown in the figure, and the rod is free to oscillate in the horizontal plane. The rod is gently pushed through a small angle theta in one direction and released. The frequency of oscillation is

  1. fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 2 k over denominator M end fraction end root    
  2. fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator k over denominator M end fraction end root    
  3. fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 6 k over denominator M end fraction end root    
  4. fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 24 k over denominator M end fraction end root    

The correct answer is: fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 6 k over denominator M end fraction end root


    Torque aboutblank P equals negative open parentheses k x close parentheses fraction numerator L over denominator 2 end fraction plus open parentheses negative k x fraction numerator L over denominator 2 end fraction close parentheses equals negative k x L equals negative k fraction numerator L to the power of 2 end exponent over denominator 2 end fraction theta
    For small angle theta comma blank x equals fraction numerator L over denominator 2 end fraction theta semicolon blank tau equals negative I alpha

    rightwards double arrow negative fraction numerator K L to the power of 2 end exponent over denominator 2 end fraction theta equals fraction numerator M L to the power of 2 end exponent over denominator 12 end fraction alpha
    rightwards double arrow fraction numerator negative 6 K theta over denominator M end fraction equals alpha
    rightwards double arrow omega equals square root of fraction numerator 6 K over denominator M end fraction end root and f equals fraction numerator omega over denominator 2 pi end fraction equals fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 6 K over denominator M end fraction end root

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