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Question

A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is left parenthesis angle P O Q equals 4 0 to the power of o end exponent right parenthesis

  1. 2 v cos invisible function application 4 0 to the power of o end exponent    
  2. 2 v sin invisible function application 4 0 to the power of o end exponent    
  3. 2 v sin invisible function application 2 0 to the power of o end exponent    
  4. 2 v cos invisible function application 2 0 to the power of o end exponent    

The correct answer is: 2 v sin invisible function application 2 0 to the power of o end exponent


    Change in velocity = 2 v sin invisible function application left parenthesis theta rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow 2 right parenthesis equals 2 v sin invisible function application 2 0 degree

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