Physics-
General
Easy

Question

A particle is projected with velocity upsilon subscript 0 end subscriptalong x minus a x i s. The deceleration on the particle is proportional to the square of the distance from the origin i.e., a equals alpha x to the power of 2 end exponent. The distance at which the particle stops is

  1. square root of fraction numerator 3 upsilon subscript 0 end subscript over denominator 2 alpha end fraction end root    
  2. open parentheses fraction numerator 3 v subscript o end subscript over denominator 2 alpha end fraction close parentheses to the power of fraction numerator 1 over denominator 3 end fraction end exponent    
  3.  square root of fraction numerator 3 v subscript 0 superscript 2 over denominator 2 alpha end fraction end root    
  4.  open parentheses fraction numerator 3 v subscript 0 superscript 2 over denominator 2 alpha end fraction close parentheses to the power of 1 third end exponent    

The correct answer is: open parentheses fraction numerator 3 v subscript 0 superscript 2 over denominator 2 alpha end fraction close parentheses to the power of 1 third end exponent


    a equals fraction numerator d v over denominator d t end fraction equals fraction numerator d v over denominator d x end fraction fraction numerator d x over denominator d t end fraction equals v fraction numerator d v over denominator d x end fraction equals negative alpha x to the power of 2 end exponent (given)
    Þ not stretchy integral subscript v subscript 0 end subscript end subscript superscript 0 end superscript v d v equals negative alpha not stretchy integral subscript 0 end subscript superscript S end superscript x to the power of 2 end exponent d x Þ open square brackets fraction numerator v to the power of 2 end exponent over denominator 2 end fraction close square brackets subscript v subscript 0 end subscript end subscript superscript 0 end superscript equals negative alpha open square brackets fraction numerator x to the power of 3 end exponent over denominator 3 end fraction close square brackets subscript 0 end subscript superscript S end superscript
    Þ fraction numerator v subscript 0 end subscript superscript 2 end superscript over denominator 2 end fraction equals fraction numerator alpha S to the power of 3 end exponent over denominator 3 end fractionÞ S equals open parentheses fraction numerator 3 v subscript 0 end subscript superscript 2 end superscript over denominator 2 alpha end fraction close parentheses to the power of fraction numerator 1 over denominator 3 end fraction end exponent

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