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Question

A piece of iron of density 7.8 cross times 10 to the power of 3 end exponent k g divided by 3 and volume 100cm3 is totally immersed in water Calculate upthrust if open parentheses d equals 1000 to the power of k g end exponent divided by m to the power of 3 end exponent close parentheses

  1. 7.8 N    
  2. 100 N    
  3. 1 N    
  4. 10 to the power of 3 end exponentN    

The correct answer is: 1 N


    Density of substance =rho subscript s end subscript equals 7.8 cross times 10 to the power of 3 end exponent k g divided by m to the power of 3 end exponent
    Density of water =rho subscript w end subscript equals 1000 k g divided by m to the power of 3 end exponent
    Volume of substance =100 c m to the power of 3 end exponent equals 100 cross times 10 to the power of negative 6 end exponent m to the power of 3 end exponent
    Volume of immersed substance=100 cross times 10 to the power of negative 6 end exponent m to the power of 3 end exponent
    g= acceleration due to gravity.
    Thus,
    upthrust =V subscript i end subscript rho subscript L end subscript g
    equals 100 cross times 10 to the power of negative 6 end exponent cross times 1000 cross times 10
    =1N

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