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Question

A planet of radius R has an acceleration due to gravity of gs on its surface. A deep smooth tunnel is dug on this planet, radially inward, to reach a point P located at a distance of fraction numerator R over denominator 2 end fraction from the centre of the planet. Assume that the planet has uniform density. The kinetic energy required to be given to a small body of mass m, projected radially outward from P, so that it gains a maximum altitude equal to the thrice the radius of the planet from its surface, is equal to

  1. fraction numerator 63 over denominator 16 end fraction m g subscript s end subscript R    
  2. fraction numerator 3 over denominator 8 end fraction m g subscript s end subscript R    
  3. fraction numerator 9 over denominator 8 end fraction m g subscript s end subscript R    
  4. fraction numerator 21 over denominator 16 end fraction m g subscript s end subscript R.    

The correct answer is: fraction numerator 9 over denominator 8 end fraction m g subscript s end subscript R


    The gravitational potential at a point Q (OQ º x) is given by :
    V left parenthesis x right parenthesis equals open curly brackets table row cell negative g subscript s end subscript R open parentheses fraction numerator 3 over denominator 2 end fraction minus fraction numerator 1 over denominator 2 end fraction fraction numerator x to the power of 2 end exponent over denominator R to the power of 2 end exponent end fraction close parentheses comma text when x < end text ​ R end cell row cell negative g subscript s end subscript R open parentheses fraction numerator R over denominator x end fraction close parentheses comma text when x > end text ​ R end cell end table close curly brackets
    The energy required to project the body, to a maximum altitude of 3R from its surface, is :
    m open parentheses V subscript B end subscript open vertical bar x equals fraction numerator R over denominator 2 end fraction minus V subscript P end subscript close vertical bar subscript x equals 4 R end subscript close parentheses equals fraction numerator 9 over denominator 8 end fraction m g subscript s end subscript R.

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