Physics-
General
Easy

Question

A rectangular loop has a sliding connector PQ of length lambda and resistance R capital omega and it is moving with a speed v as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents I subscript 1 end subscript comma I subscript 2 end subscript and I are :

  1. I subscript 1 end subscript equals negative I subscript 2 end subscript equals fraction numerator B l v over denominator R end fraction comma I equals fraction numerator 2 B l v over denominator R end fraction    
  2. I subscript 1 end subscript equals I subscript 2 end subscript equals fraction numerator B l v over denominator 3 R end fraction comma I equals fraction numerator 2 B l v over denominator 3 R end fraction    
  3. I subscript 1 end subscript equals I subscript 2 end subscript equals I equals fraction numerator B l v over denominator R end fraction    
  4. I subscript 1 end subscript equals I subscript 2 end subscript equals fraction numerator B l V over denominator 6 R end fraction comma I equals fraction numerator B l v over denominator 3 R end fraction    

The correct answer is: I subscript 1 end subscript equals I subscript 2 end subscript equals fraction numerator B l v over denominator 3 R end fraction comma I equals fraction numerator 2 B l v over denominator 3 R end fraction


    text Current  end text 1 equals fraction numerator V b l over denominator fraction numerator R over denominator 2 end fraction plus R end fraction equals fraction numerator 2 V b l over denominator 3 R end fraction

    I subscript 1 end subscript equals I subscript 2 end subscript equals fraction numerator v B l over denominator 3 R end fraction

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