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A small block of mass M moves on a frictionless surface of an inclined plane, as shown in figure. The angle of the incline suddenly changes from60 to the power of ring operator end exponent to 30 to the power of ring operator end exponentat point B. The block is initially at rest at A. Assume that collisions between the block and the incline are totally inelastic (g = 10 m divided by s to the power of 2 end exponent) If collision between the block and the incline is completely elastic, then the vertical (upward) component of the velocity of the block at point B, immediately after it strikes the second incline is :–

  1. square root of 30 m divided by s    
  2. square root of 15 m divided by s    
  3. 0    
  4. negative square root of 15 m divided by s    

The correct answer is: square root of 15 m divided by s

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