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Physics-

General

Easy

Question

Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

Increases linearly
Decreases linearly
Is constant
Increases parabolically

The correct answer is: Is constant

From acceleration-velocity graph, we have $a equals k blank v blank$ where $k$ is a constant which represents the slope of the given line.
As, $a equals v fraction numerator d v over denominator d s end fraction comma$ so $v equals fraction numerator d v over denominator d s end fraction equals k v$
or $fraction numerator d v over denominator d s end fraction equals k equals a$ constant
Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.

Related Questions to study

A cyclist starts from the centre $O$ of a circular park of radius one kilometre, reaches the edge $P$ of the park, then cycles along the circumference and returns to the centre along $Q O$ as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

A cyclist starts from the centre $O$ of a circular park of radius one kilometre, reaches the edge $P$ of the park, then cycles along the circumference and returns to the centre along $Q O$ as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is

Physics-General

If $Tanp space theta equals Cotq space theta$ then solutions of $theta$ are in -

If $Tanp space theta equals Cotq space theta$ then solutions of $theta$ are in -

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parallel

Solution of $Tan space x plus Tan space open parentheses 120 to the power of 6 plus x close parentheses plus Tan space open parentheses x minus 120 to the power of ring operator close parentheses equals 0$ is

Solution of $Tan space x plus Tan space open parentheses 120 to the power of 6 plus x close parentheses plus Tan space open parentheses x minus 120 to the power of ring operator close parentheses equals 0$ is

If $Tan space bold A plus Tan space 2 bold A plus square root of 3 Tan space bold ATan 2 bold A equals square root of 3$ then the general solution of $A over 2 equals$

If $Tan space bold A plus Tan space 2 bold A plus square root of 3 Tan space bold ATan 2 bold A equals square root of 3$ then the general solution of $A over 2 equals$

The graph between the displacement $x$ and $t$ for a particle moving in a straight line is shown in figure. During the interval $O A comma A B comma B C$ and $C D comma$ the acceleration of the particle is

$O A comma blank A B comma blank B C$ , $C D$

The graph between the displacement $x$ and $t$ for a particle moving in a straight line is shown in figure. During the interval $O A comma A B comma B C$ and $C D comma$ the acceleration of the particle is

$O A comma blank A B comma blank B C$ , $C D$

physics-General

parallel

$tan space open parentheses pi over 4 plus x over 2 close parentheses minus tan space open parentheses pi over 4 minus x over 2 close parentheses equals 2$ then the general solution of $x$ =

$tan space open parentheses pi over 4 plus x over 2 close parentheses minus tan space open parentheses pi over 4 minus x over 2 close parentheses equals 2$ then the general solution of $x$ =

Velocity-time $left parenthesis v$ - $t right parenthesis$ graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

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physics-General

In $capital delta A B C comma$ $R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals$

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parallel

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$3 Sin space x plus 4 Cos space x minus 6 equals 0$ then the general solution of $bold x$ =

Solution of $Cot squared space theta plus open parentheses square root of 3 plus fraction numerator 1 over denominator square root of 3 end fraction close parentheses Cot space theta plus 1 equals 0$ is

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The general solution of $fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1$ is

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parallel

If $Sin space A equals Sin space B comma Cos space A equals Cos space B text then end text A equals$

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If $cot space theta minus tan space theta equals 2$ then principal value of $theta$

parallel

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