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General
Easy
Question
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 2 from right then which of the following is true for image formed after a single refraction.
- Real object will result in a real image
- Virtual object will result in a virtual image
- Real object will result in a virtual image
- Virtual object will result in a Real image
The correct answer is: Virtual object will result in a Real image
Related Questions to study
physics-
All objects referred to the subsequent problems lie on the principle axis.
In above question if the object is real, then the final image formed after two refractions :
All objects referred to the subsequent problems lie on the principle axis.
In above question if the object is real, then the final image formed after two refractions :
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All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 1 from left, the image formed after the first refraction is definitely :
All objects referred to the subsequent problems lie on the principle axis.
If light is incident on surface 1 from left, the image formed after the first refraction is definitely :
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The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person
A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens
Minimum focal length of eye lens of a normal person is
The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person
A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm. A person suffering for eye defects uses spectacles (Eye glass). The function of lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina. The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3. For all the calculations required you can use the lens formula and lens maker's formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens
Minimum focal length of eye lens of a normal person is
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Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle 
, such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then
Figure I given below shows a glass vessel, partially filled with water. A narrow beam of light is incident vertically down into the water and passes straight through. Figure II shows the vessel glass tilted until the angle , such that the light is refracted along the lower surface of the glass. If refractive indices of air, water and glass are 1, 4/3 and 1.5 respectively then
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An infinitely long rectangular strip is placed on the principal axis of a concave mirror as shown in the figure. One end of the strip coincides with centre of curvature as shown. The height of rectangular strip is very small in comparison to focal length of the mirror. Then the shape of image of strip formed by concave mirror is
An infinitely long rectangular strip is placed on the principal axis of a concave mirror as shown in the figure. One end of the strip coincides with centre of curvature as shown. The height of rectangular strip is very small in comparison to focal length of the mirror. Then the shape of image of strip formed by concave mirror is
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The given lens is broken into four parts and rearranged as shown in the figure. If the initial focal length is f then after rearrangement the equivalent focal length is
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A particle revolves in clockwise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide. Call it AB. The radius of curvature of the mirror is 21 cm. Then the direction of revolution (as seen from A) of the image of the particle and its speed is
A particle revolves in clockwise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide. Call it AB. The radius of curvature of the mirror is 21 cm. Then the direction of revolution (as seen from A) of the image of the particle and its speed is
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In the figure shown find the total magnification after two successive reflections first on 
& then on 
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A square ABCD of side 1mm is kept at distance 15 cm infront of the concave mirror as shown in the figure. The focal length of the mirror is 10 cm. The length of the perimeter of its image will be :
A square ABCD of side 1mm is kept at distance 15 cm infront of the concave mirror as shown in the figure. The focal length of the mirror is 10 cm. The length of the perimeter of its image will be :
physics-General
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A convex lens of focal length f and a plane mirror are y distance apart. An object O is kept on the principal axis of the lens at a distance x from the lens. The values of x and y for the final image of O to fall exactly (position & size) on the object ‘O’
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In the figure shown a point object O is placed in air. A spherical boundary separates two media. AB is principal axis. The refractive index above AB is 1.6 and below AB is 2.0. The separation between the images formed due to refraction at spherical surface is :
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Find the value of colour coded resistance shown is fig
Find the value of colour coded resistance shown is fig
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If four resistances are connected as shown in the fig between A and B the effective resistance is
If four resistances are connected as shown in the fig between A and B the effective resistance is
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Resistance of each 10 
are connected as shown in the fig The effective resistance between A and G is
Resistance of each 10 are connected as shown in the fig The effective resistance between A and G is
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In the circuit shown, the reading of the voltmeter and the ammeter are
In the circuit shown, the reading of the voltmeter and the ammeter are
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