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Question

C subscript 2 end subscript H subscript 5 end subscript I and A g subscript 2 end subscript O reacts to produce

  1. C subscript 2 end subscript H subscript 6 end subscript    
  2. C subscript 2 end subscript H subscript 5 end subscript minus C subscript 2 end subscript H subscript 5 end subscript    
  3. C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript    
  4. C subscript 2 end subscript H subscript 5 end subscript minus C H subscript 3 end subscript    

The correct answer is: C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript


    C subscript 2 end subscript H subscript 5 end subscript I and A g subscript 2 end subscript O reacts as below
    2 C subscript 2 end subscript H subscript 5 end subscript I plus A g subscript 2 end subscript O rightwards arrow stack C subscript 2 end subscript H subscript 5 end subscript O C subscript 2 end subscript H subscript 5 end subscript with text ether end text below plus I subscript 2 end subscript
    Thus, C subscript 2 end subscript H subscript 5 end subscript minus O minus C subscript 2 end subscript H subscript 5 end subscript is produced

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