Physics-
General
Easy

Question

Energy levels A, B, C of a certain atom corresponding to increasing values of energy, i. e. comma blank E subscript A end subscript less than E subscript B end subscript less than E subscript C end subscript. If lambda subscript 1 end subscript comma lambda subscript 2 end subscript comma lambda subscript 3 end subscript are the wavelength of radiations corresponding to the transitions C to B comma B to A and C to A respectively, which of the following statements is correct

  1. lambda subscript 3 end subscript equals lambda subscript 1 end subscript plus lambda subscript 2 end subscript    
  2. lambda subscript 3 end subscript equals fraction numerator lambda subscript 1 end subscript lambda subscript 2 end subscript over denominator lambda subscript 1 end subscript plus lambda subscript 2 end subscript end fraction    
  3. lambda subscript 1 end subscript plus lambda subscript 2 end subscript plus lambda subscript 3 end subscript equals 0    
  4. lambda subscript 3 end subscript superscript 2 end superscript equals lambda subscript 1 end subscript superscript 2 end superscript plus lambda subscript 2 end subscript superscript 2 end superscript    

The correct answer is: lambda subscript 3 end subscript equals fraction numerator lambda subscript 1 end subscript lambda subscript 2 end subscript over denominator lambda subscript 1 end subscript plus lambda subscript 2 end subscript end fraction


    Let the energy in A comma B and C states be E subscript A end subscript. E subscript B end subscript and E subscript C end subscript, then from the figure

    open parentheses E subscript C end subscript minus E subscript B end subscript close parentheses plus open parentheses E subscript B end subscript minus E subscript A end subscript close parentheses equals left parenthesis E subscript C end subscript minus E subscript A end subscript right parenthesis or fraction numerator h c over denominator lambda subscript 1 end subscript end fraction plus fraction numerator h c over denominator lambda subscript 2 end subscript end fraction equals fraction numerator h c over denominator lambda subscript 3 end subscript end fraction
    rightwards double arrow lambda subscript 3 end subscript equals fraction numerator lambda subscript 1 end subscript lambda subscript 2 end subscript over denominator lambda subscript 1 end subscript plus lambda subscript 2 end subscript end fraction

    Related Questions to study

    General
    physics-

    Binding energy per nucleon plot against the mass number for stable nuclei is shown in the figure. which curve is correct

    Binding energy per nucleon plot against the mass number for stable nuclei is shown in the figure. which curve is correct

    physics-General
    General
    physics-

    Drawings I and II show two samples of electric field lines

    Drawings I and II show two samples of electric field lines

    physics-General
    General
    physics-

    Figure shows lines of force for a system of two point charges. The possible choice for the charges is

    Figure shows lines of force for a system of two point charges. The possible choice for the charges is

    physics-General
    parallel
    General
    physics-

    Figure shows the electric lines of force emerging from a charged body. If the electric field at ‘A’ and ‘B’ are EA and EB respectively and if the displacement between ‘A’ and ‘B’ is ‘r’ then

    Figure shows the electric lines of force emerging from a charged body. If the electric field at ‘A’ and ‘B’ are EA and EB respectively and if the displacement between ‘A’ and ‘B’ is ‘r’ then

    physics-General
    General
    physics-

    Four charges are arranged at the corners of a square ABCD as shown in the figure. The force on the positive charge kept at the centre ‘O’ is

    Four charges are arranged at the corners of a square ABCD as shown in the figure. The force on the positive charge kept at the centre ‘O’ is

    physics-General
    General
    physics-

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The time interval between minimum and maximum frequency as received by the detector

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The time interval between minimum and maximum frequency as received by the detector

    physics-General
    parallel
    General
    physics-

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The time at which the detector will hear the maximum frequency for the 1st time

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The time at which the detector will hear the maximum frequency for the 1st time

    physics-General
    General
    physics-

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The frequency as received by the detector when it rotates by an angle fraction numerator pi over denominator 2 end fraction

    A detector is moving in a circular path of radius r in anticlock wise direction with a constant angular velocity omega as shown in the figure At time t=0, it starts from the location shown at A, assuming source at rest The frequency as received by the detector when it rotates by an angle fraction numerator pi over denominator 2 end fraction

    physics-General
    General
    physics-

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s If he continous to walk along the same line how many more maxima can he hear

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s If he continous to walk along the same line how many more maxima can he hear

    physics-General
    parallel
    General
    physics-

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s The angle θ at which he will hear maximum intensity for first time?

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s The angle θ at which he will hear maximum intensity for first time?

    physics-General
    General
    physics-

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s The angle θ at which intensity of sound drop to a minimum for the first time

    Two speakers S subscript 1 end subscript & S subscript 2 end subscript driven by the same amplifiers are placed at y=1m and y=-1m The speakers vibrate in phase at 600 Hz A man stands at a point on x-axis at a very large distance form the origin and starts moving parallel to y-axis The speed of sound in air is 330 m/s The angle θ at which intensity of sound drop to a minimum for the first time

    physics-General
    General
    physics-

    When a composite wire is made by joining two wires as shown in figure and possible frequencies of this wire is asked (both ends fixed) then the lowest frequency is that at which individual lowest frequencies of the two wires are equal text In the figure given :  end text l subscript 1 end subscript equals l subscript 2 end subscript equals l. mu subscript 1 end subscript equals fraction numerator mu subscript 2 end subscript over denominator 9 end fraction equals mu text  . end textThe lowest frequency such that the junction is an antinode is

    When a composite wire is made by joining two wires as shown in figure and possible frequencies of this wire is asked (both ends fixed) then the lowest frequency is that at which individual lowest frequencies of the two wires are equal text In the figure given :  end text l subscript 1 end subscript equals l subscript 2 end subscript equals l. mu subscript 1 end subscript equals fraction numerator mu subscript 2 end subscript over denominator 9 end fraction equals mu text  . end textThe lowest frequency such that the junction is an antinode is

    physics-General
    parallel
    General
    physics-

    When a composite wire is made by joining two wires as shown in figure and possible frequencies of this wire is asked (both ends fixed) then the lowest frequency is that at which individual lowest frequencies of the two wires are equal text In the figure given :  end text l subscript 1 end subscript equals l subscript 2 end subscript equals l. mu subscript 1 end subscript equals fraction numerator mu subscript 2 end subscript over denominator 9 end fraction equals mu text  . end textThe lowest frequency such that the junction is a node is

    When a composite wire is made by joining two wires as shown in figure and possible frequencies of this wire is asked (both ends fixed) then the lowest frequency is that at which individual lowest frequencies of the two wires are equal text In the figure given :  end text l subscript 1 end subscript equals l subscript 2 end subscript equals l. mu subscript 1 end subscript equals fraction numerator mu subscript 2 end subscript over denominator 9 end fraction equals mu text  . end textThe lowest frequency such that the junction is a node is

    physics-General
    General
    physics-

    A heavy but uniform rope of length L is suspended from a ceiling A particle is dropped from the ceiling at the same instant the bottom end is given the jerk where will the particle meet the pulse measured from bottom?

    A heavy but uniform rope of length L is suspended from a ceiling A particle is dropped from the ceiling at the same instant the bottom end is given the jerk where will the particle meet the pulse measured from bottom?

    physics-General
    General
    physics-

    A heavy but uniform rope of length L is suspended from a ceiling If the rope is given a sudden sideways jerk at the bottom, how long will it take for the pulse to reach the ceiling?

    A heavy but uniform rope of length L is suspended from a ceiling If the rope is given a sudden sideways jerk at the bottom, how long will it take for the pulse to reach the ceiling?

    physics-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.