Physics-
General
Easy

Question

Equal current i flows in two segments of a circular loop in the direction shown in figure. Radius of the loop is r. The magnitude of magnitude field induction at the centre of the loop is

  1. zero    
  2. fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator i theta over denominator r end fraction    
  3. fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i over denominator r end fraction open parentheses pi minus theta close parentheses    
  4. fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i over denominator r end fraction left parenthesis 2 pi minus theta right parenthesis    

The correct answer is: fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i over denominator r end fraction open parentheses pi minus theta close parentheses


    Magnetic field induction at O due to current through A C B blank i s B subscript 1 end subscript equals fraction numerator mu subscript 0 end subscript i theta over denominator 4 pi r end fraction
    It is acting perpendicular to the paper downwards.
    Magnetic field induction at O due to current through A B D blank i s B subscript 2 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator i left parenthesis 2 pi minus theta right parenthesis over denominator r end fraction
    It is acting perpendicular to paper upwards.
    therefore blank Total magnetic field at O due to current loop is
    B equals B subscript 2 end subscript minus B subscript 1 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator i over denominator r end fraction open parentheses 2 pi minus theta close parentheses fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator i over denominator r end fraction theta
    equals blank fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i over denominator r end fraction blank left parenthesis pi minus theta right parenthesis

    Related Questions to study

    General
    physics-

    A wire carrying current i is shaped as shown. Section A B is a quarter circle of radius r. The magnetic field is directed

    A wire carrying current i is shaped as shown. Section A B is a quarter circle of radius r. The magnetic field is directed

    physics-General
    General
    physics-

    Two wires A blank a n d blank B carry currents as shown in figure. The magnetic interactions

    Two wires A blank a n d blank B carry currents as shown in figure. The magnetic interactions

    physics-General
    General
    physics-

    A uniform conducting wire A B C has a mass of 10 g. A current of 2 A flows through it. The wire is kept in a uniform magnetic field B equals 2 T. The acceleration of the wire will be

    A uniform conducting wire A B C has a mass of 10 g. A current of 2 A flows through it. The wire is kept in a uniform magnetic field B equals 2 T. The acceleration of the wire will be

    physics-General
    parallel
    General
    physics-

    Two long straight wires are set parallel to each other. Each carries a current i in the opposite direction and the separation between them is 2 R. The intensity of the magnetic field midway between them is

    Two long straight wires are set parallel to each other. Each carries a current i in the opposite direction and the separation between them is 2 R. The intensity of the magnetic field midway between them is

    physics-General
    General
    physics-

    P Q R Sis a square loop made of uniform wire. If the current enters the loop at P and leaves at S, then the magnetic field will be

    P Q R Sis a square loop made of uniform wire. If the current enters the loop at P and leaves at S, then the magnetic field will be

    physics-General
    General
    physics-

    Two wires with currents 2 A and 1A are enclosed in a circular loop. Another wire with current 3 A is situated outside the loop as shown. The not stretchy contour integral stack B with rightwards arrow on top. d stack l with rightwards arrow on top around the loop is 

    Two wires with currents 2 A and 1A are enclosed in a circular loop. Another wire with current 3 A is situated outside the loop as shown. The not stretchy contour integral stack B with rightwards arrow on top. d stack l with rightwards arrow on top around the loop is 

    physics-General
    parallel
    General
    physics-

    Following figure shows the path of an electron that passes through two regions containing uniform magnetic fields of magnitudes B subscript 1 end subscriptand B subscript 2 end subscript. It’s path in each region is a half circle, choose the correct option

    Following figure shows the path of an electron that passes through two regions containing uniform magnetic fields of magnitudes B subscript 1 end subscriptand B subscript 2 end subscript. It’s path in each region is a half circle, choose the correct option

    physics-General
    General
    chemistry-

    Number. Of atoms in"4.25 g of NH3 is:

    Number. Of atoms in"4.25 g of NH3 is:

    chemistry-General
    General
    chemistry-

    H subscript 2 end subscript S contains 5.88% hydrogen, H subscript 2 end subscript O ~ontains 11.11 % hydrogen while S02 contains 50% sulphur These figures jllustrate the law of:

    H subscript 2 end subscript S contains 5.88% hydrogen, H subscript 2 end subscript O ~ontains 11.11 % hydrogen while S02 contains 50% sulphur These figures jllustrate the law of:

    chemistry-General
    parallel
    General
    chemistry-

    Potassium combines with two isotopes of chlorine eSCI and 37CI respectively to form two samples of KCI Their formation follows the law of:

    Potassium combines with two isotopes of chlorine eSCI and 37CI respectively to form two samples of KCI Their formation follows the law of:

    chemistry-General
    General
    chemistry-

    S02 gas was prepared by
    i) burning Sulphur in oxygen,
    ii) reacting sodium sulphite with dilute H subscript 2 end subscript S O subscript 4 end subscript and
    iii) heating copper with conc H subscript 2 end subscript S O subscript 4 end subscript, It was found that in each case sulphur and oxygen combined in the ratio of 1 : 1The data illustrates the law of:

    S02 gas was prepared by
    i) burning Sulphur in oxygen,
    ii) reacting sodium sulphite with dilute H subscript 2 end subscript S O subscript 4 end subscript and
    iii) heating copper with conc H subscript 2 end subscript S O subscript 4 end subscript, It was found that in each case sulphur and oxygen combined in the ratio of 1 : 1The data illustrates the law of:

    chemistry-General
    General
    Chemistry

    Among the following the strongest nucleophile is

    Among the following the strongest nucleophile is

    ChemistryGeneral
    parallel
    General
    chemistry-

    Consider the Hofmann ammonolysis reaction

    For any value of R, the correct order of basic character of the above amines in gaseous phase of nonpolar solvent is:

    Consider the Hofmann ammonolysis reaction

    For any value of R, the correct order of basic character of the above amines in gaseous phase of nonpolar solvent is:

    chemistry-General
    General
    chemistry-

    Consider the Hofmann ammonolysis reaction

    If R equals M e subscript 3 end subscript C- (butyl), the correct order of basic char acter of the above amines in aqueous medium is:

    Consider the Hofmann ammonolysis reaction

    If R equals M e subscript 3 end subscript C- (butyl), the correct order of basic char acter of the above amines in aqueous medium is:

    chemistry-General
    General
    chemistry-

    Consider the Hofmann ammonolysis reaction

    lf R equals M e subscript 2 end subscript C H- (isopropyl), the correct order of basic character of the above amines in aqueous medium is

    Consider the Hofmann ammonolysis reaction

    lf R equals M e subscript 2 end subscript C H- (isopropyl), the correct order of basic character of the above amines in aqueous medium is

    chemistry-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.